C程序数组和for循环练习

Question

我必须编写一个函数来使用 for 循环检查一个值是否位于具有 N 个元素的数组中。我编写了代码

 #include <stdio.h>
int main ()
int N[100],n,i; 
printf ("Write the value of n:");
scanf ("%d",&n);
i=0;

      printf ("Write the value of the element :");
      scanf ("%d",&v[i]);
      for (i=0,i<n,i++)
      {
          if (N[i]==n)
          }
          printf ("The value is located in the array :");



return 0;               

当我编译它时，它在 printf 之前说语法错误。这是什么意思？我做错了什么？

Answer 1

基本语法问题。尝试:

#include <stdio.h>

int main(void)
{
    int N[100],n,i; 
    printf ("Write the value of n:");
    scanf ("%d",&n);
    i=0;
    printf("Write the value of the element :");
    scanf("%d", &v[i]);  /* v doesn't exist */

    /* you are looping up to n, which could be anything */
    for (i=0; i<n; i++)
    {
        /* you never populate N, so why would you expect n to be found?
        the value of any element in N is indeterminate at this point */
        if (N[i]==n)
        {
            printf ("The value is located in the array :");
        }
    }      

    return 0;
}

---

也就是说，你这里有逻辑问题:

1. v 未在任何地方声明。
2. 您永远不会填充数组 (N)。
3. n是用户输入的值，不是数组的上限。如果我输入 101 会怎么样？

这些不仅仅是语法问题，您还需要修复您的逻辑。