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我正在尝试使用 Simple-H HV 电机屏蔽和 H 桥连接来控制单个直流电机。我需要使用串行监视器控制速度和方向(例如“f 220”表示以 220 的速度前进)。这是我的代码:
M1使电机前进，M2使电机后退。
这是错误:没有匹配函数来调用“HardwareSerial::print()”
我不知道这是否是正确的编码方式。我只是想在编程方面得到一些帮助，因为我在 Arduino 编码方面还很陌生。
const int PWM1 = 2; //PA - PWM A (M1)
const int PWM2 = 3; //PB - PWM B (M2)
const int MotorEnable = 4; //EA - Enable A
const int TestLED = 13; //LED that tests whether going forward or back. LED lights up = forward, //non-lit = reverse
void setup() {
pinMode(PWM1, OUTPUT);
pinMode(PWM2, OUTPUT);
Serial.begin(9600);
}
void loop() {
int VariableMove = Serial.print(); // *** ERROR is here! ***
int speed = Serial.parseInt();
if (Serial.available() > 0) {
if (VariableMove = "f" && speed >= 0 && speed <= 255) {
digitalWrite(MotorEnable, HIGH);
digitalWrite(PWM1, HIGH);
digitalWrite(PWM2, LOW);
Serial.println("Going Forward");
analogWrite(PWM1, speed);
}
if (VariableMove = "r" && speed >= 0 && speed <= 255) {
digitalWrite(MotorEnable, HIGH);
digitalWrite(PWM1, LOW);
digitalWrite(PWM2, HIGH);
Serial.println("Coming Back");
analogWrite(PWM2, speed);
}
}
}