我可以使用 libcurl 发送 Json 字符串吗?我对两者都不熟悉。任何形式的帮助将不胜感激。基本上我想在 C 中使用 libcurl 简单发送和接收发送一个 Json 字符串
我的代码如下:
#include <stdio.h>
#include <string.h>
#include <curl/curl.h>
/* Auxiliary function that waits on the socket. */
static int wait_on_socket(curl_socket_t sockfd, int for_recv, long timeout_ms)
{
struct timeval tv;
fd_set infd, outfd, errfd;
int res;
tv.tv_sec = timeout_ms / 1000;
tv.tv_usec= (timeout_ms % 1000) * 1000;
FD_ZERO(&infd);
FD_ZERO(&outfd);
FD_ZERO(&errfd);
FD_SET(sockfd, &errfd); /* always check for error */
if(for_recv)
{
FD_SET(sockfd, &infd);
}
else
{
FD_SET(sockfd, &outfd);
}
/* select() returns the number of signalled sockets or -1 */
res = select(sockfd + 1, &infd, &outfd, &errfd, &tv);
return res;
}
int main(void)
{
CURL *curl;
CURLcode res;
/* Minimalistic http request */
const char *request = "reactantsJSON={"O=O":{"N":1}}&productsJSON=["O=O","[O]"]&temperature=2273.15&pressure=101.325";
curl_socket_t sockfd; /* socket */
long sockextr;
size_t iolen;
curl = curl_easy_init();
if(curl) {
curl_easy_setopt(curl, CURLOPT_URL, "http://gibbs.sdsu.edu:8080/axis2/services/GibbsMinimization/solveTP");
/* Do not do the transfer - only connect to host */
curl_easy_setopt(curl, CURLOPT_CONNECT_ONLY, 1L);
res = curl_easy_perform(curl);
if(CURLE_OK != res)
{
printf("Error: %s\n", strerror(res));
return 1;
}
/* Extract the socket from the curl handle - we'll need it for waiting.
* Note that this API takes a pointer to a 'long' while we use
* curl_socket_t for sockets otherwise.
*/
res = curl_easy_getinfo(curl, CURLINFO_LASTSOCKET, &sockextr);
if(CURLE_OK != res)
{
printf("Error: %s\n", curl_easy_strerror(res));
return 1;
}
sockfd = sockextr;
/* wait for the socket to become ready for sending */
if(!wait_on_socket(sockfd, 0, 60000L))
{
printf("Error: timeout.\n");
return 1;
}
puts("Sending request.");
/* Send the request. Real applications should check the iolen
* to see if all the request has been sent */
res = curl_easy_send(curl, request, strlen(request), &iolen);
if(CURLE_OK != res)
{
printf("Error: %s\n", curl_easy_strerror(res));
return 1;
}
puts("Reading response.");
/* read the response */
for(;;)
{
char buf[1024];
wait_on_socket(sockfd, 1, 60000L);
res = curl_easy_recv(curl, buf, 1024, &iolen);
if(CURLE_OK != res)
break;
printf("Received %u bytes.\n", iolen);
}
/* always cleanup */
curl_easy_cleanup(curl);
}
return 0;
}
我得到的错误是它说一个“;”在第 40 行中丢失,它只是 json 字符串,即使我有一个“;”在那条线上。看起来我需要发送 json 字符串来做一些我不知道的事情。我是否需要在编译代码时指定一些标志。
最佳答案
const char *request = "reactantsJSON={"O=O":{"N":1}}&productsJSON=["O=O","[O]"]&temperature=2273.15&pressure=101.325";
您需要在字符串文字中转义 "
。
const char *request = "reactantsJSON={\"O=O\":{\"N\":1}}&productsJSON=[\"O=O\",\"[O]\"]&temperature=2273.15&pressure=101.325";
关于c - libcurl 中的 Json 字符串,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/7351406/