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Possible Duplicate:
What is a fast C or Objective-C math parser?
我可以使用什么函数代码将动态字符串转换为表达式并对其求值？
#include <stdio.h>
#include <conio.h>
#include <string.h>
int main() {
char var1[] = "3";
char var2[] = "2";
char var3[] = "5";
char exp[20] = "";
int result;
// Trying to create a random expression "(3+2)*5"
strcat(exp, "( ");
strcat(exp, var1);
strcat(exp, " + ");
strcat(exp, var2);
strcat(exp, " ) * ");
strcat(exp, var3);
result = somefunction(exp);
printf("Result : %i\n", result);
return 0;
}