c - 地址的值(value)。给出异常(exception)

Question

我正在尝试在微 Controller 上打印一段内存。

它提示这条线:

stringLength += sprintf(buffer + stringLength, "0x%X, ", *(startAddress + i));

由于:

*(startAddress + i)

为什么这不起作用？它不应该只给我地址的值吗？

在 ARM 微 Controller 上工作，它会跳转到 HardFault_Handler()(通常表示非法内存访问)。

我怎样才能明智地获取内存位置的值？

整个函数:

void printMemory(uint32_t *startAddress, uint32_t lengthInBytes)
{
    uint32_t stringLength = 0;
    uint32_t i;
    char buffer[1000];
    uint32_t start = (uint32_t) startAddress;

    for (i = start; i < (start + lengthInBytes); i++)
    {
        if ((i % 10) == 0)
        {
            stringLength += sprintf(buffer + stringLength, "\r\n");
        }

        stringLength += sprintf(buffer + stringLength, "0x%X, ", *(startAddress + i));
    }

    //Add line termination.
    stringLength += sprintf(buffer + strlen(buffer), "%c", '\0');

    //Printf buffer.
    printf("%s", &buffer[0]);
}

编辑:

工作示例:

void printMemory(uint32_t startAddress, uint32_t lengthInBytes)
{
    uint32_t i;
    char buffer[1000];
    uint32_t stringLength = 0;
    uint8_t *start;

    //Create a uint8_t pointer to address.
    start = (uint8_t *) startAddress;

    for (i = 0; i < lengthInBytes; i++)
    {
        if ((i % 10) == 0)
        {
            stringLength += sprintf(buffer + stringLength, "\r\n");
        }

        stringLength += sprintf(buffer + stringLength, "0x%X, ", *(start + i));
    }

    //Add line termination.
    stringLength += sprintf(buffer + strlen(buffer), "%c", '\0');

    //Printf buffer.
    printf("%s", &buffer[0]);
}

Answer 1

你犯了一个错误:

i 从 start 开始，也就是 startAddress，所以在第一次迭代中你正在获取:

*(startAddress + startAddress)