我正在尝试将一个数组的十六进制值转换为另一个数组的字符。这是唯一的方法,我能找到但不起作用。
感谢您的帮助!
char tmp[] = {0x81, 0x00, 0x00, 0x00, 0x12, 0x05};
char new[12];
for (int i = 0; i < 6; i++) {
printf(" %x", tmp[i]);
sprintf(new + i, "%x", tmp[i]);
}
for (int i = 0; i < 12; i++) {
printf(" %c", new[i]);
}
printf("new: %s\n", new);
这是输出:
81 0 0 0 12 5
8 0 0 0 1 5
new: 800015
所以,它缺少一些字节......
最佳答案
可能
char tmp[] = {0x81, 0x00, 0x00, 0x00, 0x12, 0x05};
char new[6];
必须是
int tmp[] = {0x81, 0x00, 0x00, 0x00, 0x12, 0x05};
char new[6*2+1];
和
sprintf(tmp + i, "%x", tmp[i]);
必须是
sprintf(new + 2*i, "%02x", tmp[i]);
和
for (int i = 0; i < 6; i++) {
printf(" %c", new[i]);
}
必须是
for (int i = 0; i < 6*2; i++) {
printf(" %c", new[i]);
}
执行:
/tmp % ./a.out
81 0 0 0 12 5 8 1 0 0 0 0 0 0 1 2 0 5new: 810000001205
在 valgrind 下:
/tmp % valgrind ./a.out
==15557== Memcheck, a memory error detector
==15557== Copyright (C) 2002-2012, and GNU GPL'd, by Julian Seward et al.
==15557== Using Valgrind-3.8.1 and LibVEX; rerun with -h for copyright info
==15557== Command: ./a.out
==15557==
81 0 0 0 12 5 8 1 0 0 0 0 0 0 1 2 0 5new: 810000001205
==15557==
==15557== HEAP SUMMARY:
==15557== in use at exit: 0 bytes in 0 blocks
==15557== total heap usage: 0 allocs, 0 frees, 0 bytes allocated
==15557==
==15557== All heap blocks were freed -- no leaks are possible
==15557==
==15557== For counts of detected and suppressed errors, rerun with: -v
==15557== ERROR SUMMARY: 0 errors from 0 contexts (suppressed: 6 from 6)
关于将数组的十六进制值转换为另一个数组的字符串值,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/54575278/