C 错误 : C2040: 'customerPtr' : 'int' differs in levels of indirection from 'customer *'

Question

C 的新手。当我运行讲师给我们的代码时，我总是收到此错误。

#include <stdio.h>
#include <stdlib.h>
#include <math.h>
#include <string.h>
#include <time.h>
#include <stdlib.h>

//Create a struct for customers
struct customer
{
char lastName[15];
char firstName[15];
unsigned int customerNumber;
};


struct customer customerRecord;
struct customer *customerPtr;
struct customer other;

customerPtr = &customerRecord;

//typedef struct customer to customer
typedef struct customer customer;

char main()
{
//customerRecord.lastName = Flacco;

}

我得到了错误 错误 C2040:“customerPtr”:“int”的间接级别与“customer *”不同

我读过其他类似的帖子，但我想我不明白
中的答案 与他们的计划有关。

谢谢!

Answer 1

这个赋值是错误的(在全局范围内不允许赋值):

customerPtr = &customerRecord;

你应该改变它:

...
struct customer customerRecord;
struct customer *customerPtr = &customerRecord;  /* definition & initialization */
struct customer other;
...

或

struct customer customerRecord;
struct customer *customerPtr;  /* definition */
struct customer other;

...

int main()
{
  customerPtr = &customerRecord;  /* initialization */

  ...
}

同时 main 的返回类型应该是 int