我一直收到 Segmentation Fault (core dumped)
运行时错误,我不知道为什么。
我的代码:
struct Node
{
void *next;
void *val;
};
typedef struct Node* NodePtr;
struct List
{
NodePtr head;
};
typedef struct List* ListPtr;
ListPtr create()
{
ListPtr ptr = malloc(sizeof(struct List));
return ptr;
}
int insert(ListPtr list, void *obj)
{
NodePtr newObj = malloc(sizeof(struct Node));
//Cast next as a self referencing Node
newObj->next = (NodePtr) newObj->next;
//Point to beginning of list
NodePtr current = list->head;
if(list->head == NULL)
{
newObj->val = obj;
list->head->next = newObj;
newObj->next = NULL;
return 1;
}
return 0;
}
int main(int argc, char *argv[])
{
int x = 2;
int *p = &x;
ListPtr thing = create();
insert(thing, p);
return 0;
}
错误在这里:list->head->next = newObj
经过一些调试。我以为我必须为 list->head->next 分配内存,但是当我为此添加代码时,它仍然给了我同样的错误。我是投错了还是没有正确分配内存?任何帮助将不胜感激,谢谢!
最佳答案
把它放在一起,运行良好。
#include <stdlib.h>
#include <stdio.h>
struct Node {
void *next;
void *val;
};
typedef struct Node* NodePtr;
struct List {
NodePtr head;
};
typedef struct List* ListPtr;
ListPtr CreateList() {
ListPtr ptr = malloc(sizeof(struct List));
return ptr;
}
void Insert(ListPtr list, void *obj) {
// create and initialize new node
NodePtr newObj = malloc(sizeof(struct Node));
newObj->val = obj;
newObj->next = NULL;
//Point to beginning of list
NodePtr curr = list->head;
// Add node to the list
if(curr == NULL) // if no head node, make newObj the head node
{
list->head = newObj;
}
else{ // otherwise traverse the list until you find the last node (the one that points to a null as the next)
while(1) {
if(curr->next != NULL) {
curr = curr -> next;
} else {
curr->next = newObj;
}
list->head = newObj;
newObj->val = obj;
list->head->next = newObj;
newObj->next = NULL;
}
}
}
int main() {
int x = 2;
int *p = &x;
ListPtr thing = CreateList();
Insert(thing, p);
return 0;
}
关于C Segmentation Fault (core dumped) 链表,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/32875500/