标签 c
<分区>
我用C写了下面的代码:
#include <stdio.h>
#include <stdlib.h>
int main (int argc , char *argv[]) {
int * ptr = (int *)malloc(sizeof(int));
int three = 3;
ptr = &three;
free(ptr);
return EXIT_SUCCESS;
}
当我执行时出现以下错误:
Abort signal from abort(3) (SIGABRT).
你能帮我找出我的错误吗？ 谢谢你!
最佳答案
您拥有的是未定义的行为。 C11 标准规定:
7.22.3.3 The free function
...
2 The free function causes the space pointed to by ptr to be deallocated, that is, made available for further allocation. If ptr is a null pointer, no action occurs. Otherwise, if the argument does not match a pointer earlier returned by a memory management function, or if the space has been deallocated by a call to free or realloc, the behavior is undefined.
在您的示例中，free 的参数是 &three，它不是内存管理函数返回的指针，因此您具有所看到的行为。
关于C 指针 + 空闲 : Abort signal from abort(3) (SIGABRT)，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/54824140/