这段代码
int
main (void)
{
int i;
char pmbbuf[4];
wchar_t *pwchello = L"1234567890123456789012345678901234567890";
i = wcstombs (pmbbuf, pwchello, wcslen(pwchello)* MB_CUR_MAX + 1);
printf("%d\n", MB_CUR_MAX);
printf (" Characters converted: %u\n", i);
printf (" Multibyte character: %s\n\n", pmbbuf);
return 0;
}
奇怪的是它编译时没有警告。
当我运行 ./a.out 时它打印出来 1个 字符转换:40 多字节字符:1234(
段错误
对段错误有什么想法吗?
TIA, 类别
最佳答案
您遇到缓冲区溢出是因为您没有在转换后以 null 终止缓冲区,而且缓冲区大小也不足以保存结果。
您可以动态分配内存,因为您事先不知道需要多少内存:
int i;
char pmbbuf*;
wchar_t *pwchello = L"1234567890123456789012345678901234567890";
// this will not write anything, but return the number of bytes in the result
i = wcstombs (0, pwchello, wcslen(pwchello)* MB_CUR_MAX + 1);
//allocate memory - +1 byte for the trailing null, checking for null pointer returned omitted (though needed)
pmbbuf = malloc( i + 1 );
i = wcstombs (pmbbuf, pwchello, wcslen(pwchello)* MB_CUR_MAX + 1);
//put the trailing null
pmbbuf[i] = 0;
//whatever you want to do with the string - print, e-mail, fax, etc.
// don't forget to free memory
free( pmbbuf );
//defensive - to avoid misuse of the pointer
pmbbuf = 0;
关于c - wcstombs 段错误,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/2279955/