计算字符数组中的字符？

Question

目前我正在尝试根据每个单词的第一个字符对段落进行排序。我正在初始化两个字母(Upper 和 Lower)字符数组，以将单词的第一个字符与数组索引进行比较。

我对问题的计划；

• 用字母表初始化两个数组，以了解哪个字母表在哪个之前。
• 有一个函数实际比较第一个字符和两个数组。
• 返回排序后的单词 :)

我的问题是我试图查看这两个数组是否有 26 个字符以确保每个字母都被计算在内，但它打印出 1，我不知道为什么。

代码:

#include <stdio.h>

int main(int argc, const char * argv[]) {

    char _alphabetUpperCase[100] = {"A","B","C","D","E","F","G","H","I","J","K","L","M","N","O","P","Q","R,","S","T","U","V","W","X","Y","Z"};
    char _alpabetLowerCase[100] = {"a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z"};

    int i = 0;
    int n = 0;
    while(_alpabetLowerCase[i] != NULL)
    {
        n = n+1;
        i++;
    }

    printf("%d\n",n);
    return 0;
}

Answer 1

这个“A”与“A”不同。您应该将“A”分配给一个字符。 用相应的 '' 字符替换所有 ""字符串。例如

char _alpabetLowerCase[100] = {'a','b','c' ... };