我试图在循环中生成长度为 16
的随机整数数组。数组的元素将位于 [0, 255]
内。我认为从 [0, 255]
分配随机整数就足够了;但它不起作用(创建一个随机数组,在迭代过程中保持不变)。然后我尝试了洗牌,但情况并没有改善(我还注意到 'random' 数组中 0
的概率明显更大)。
这是我的代码:
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
//#define Shuffle
/* Generate a random integer array of length `size` with elements from [0, 255] */
int* random_sample(int size)
{
int i, j, k;
int *elements = malloc(size*sizeof(int));
/* Assign random integers */
for (i = size - 1; i > 0; --i)
{
elements[i] = rand() % 256;
}
/* Shuffle */
#ifdef Shuffle
for (i = size - 1; i > 0; --i) {
j = rand() % size;
k = elements[i];
elements[i] = elements[j];
elements[j] = k;
}
#endif
return elements;
}
int main(int argc, char const *argv[])
{
int LENGTH = 16, i, iteration;
int *random_array = random_sample(LENGTH);
srand(time(NULL));
for (iteration = 0; iteration < 10; ++iteration)
{
for (i = 0; i < LENGTH; ++i)
printf("%d, ", random_array[i]);
puts("");
}
return 0;
}
典型的输出如下:
0, 227, 251, 242, 171, 186, 205, 41, 236, 74, 255, 81, 115, 105, 198, 103,
0, 227, 251, 242, 171, 186, 205, 41, 236, 74, 255, 81, 115, 105, 198, 103,
0, 227, 251, 242, 171, 186, 205, 41, 236, 74, 255, 81, 115, 105, 198, 103,
0, 227, 251, 242, 171, 186, 205, 41, 236, 74, 255, 81, 115, 105, 198, 103,
0, 227, 251, 242, 171, 186, 205, 41, 236, 74, 255, 81, 115, 105, 198, 103,
0, 227, 251, 242, 171, 186, 205, 41, 236, 74, 255, 81, 115, 105, 198, 103,
0, 227, 251, 242, 171, 186, 205, 41, 236, 74, 255, 81, 115, 105, 198, 103,
0, 227, 251, 242, 171, 186, 205, 41, 236, 74, 255, 81, 115, 105, 198, 103,
0, 227, 251, 242, 171, 186, 205, 41, 236, 74, 255, 81, 115, 105, 198, 103,
0, 227, 251, 242, 171, 186, 205, 41, 236, 74, 255, 81, 115, 105, 198, 103,
我尝试了上述代码的几种变体,但都不起作用。需要帮助!
编辑
我正在尝试代码的变体,并错误地打印了相同的未更改数组(正如其他人所指出的 - 感谢他们);原来是我写的
int main(int argc, char const *argv[])
{
int LENGTH = 16, i, iteration;
int *random_array;
srand(time(NULL));
for (iteration = 0; iteration < 10; ++iteration)
{
random_array = random_sample(LENGTH);
for (i = 0; i < LENGTH; ++i)
printf("%d, ", random_array[i]);
puts("");
}
return 0;
}
打印更多的 0
。
编辑 (2)
感谢@pmg,我找到了问题所在。在 random_sample
函数中,改变第一个
for (i = size - 1; i > 0; --i)
到 for (i = size - 1; i >= 0; --i)
工作正常!
谢谢大家
最佳答案
试试下面的代码。对于在每次迭代中包含不同(随机)值的数组,您需要在其中放入不同的值:)
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
//#define Shuffle
/* Generate a random integer array of length `size` with elements from [0, 255] */
int* random_sample(int size)
{
int i, j, k;
int *elements = malloc(size*sizeof(int));
/* Assign random integers */
for (i = size - 1; i > 0; --i)
{
elements[i] = rand() % 256;
}
/* Shuffle */
#ifdef Shuffle
for (i = size - 1; i > 0; --i) {
j = rand() % size;
k = elements[i];
elements[i] = elements[j];
elements[j] = k;
}
#endif
return elements;
}
int main(int argc, char const *argv[])
{
int LENGTH = 16, i, iteration;
int *random_array;
srand(time(NULL));
for (iteration = 0; iteration < 10; ++iteration)
{
random_array = random_sample(LENGTH);
for (i = 0; i < LENGTH; ++i)
printf("%d, ", random_array[i]);
puts("");
free(random_array);
}
return 0;
}
关于c - 在 C 中的循环中生成一个随机整数数组,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/23137568/