c++ - 读取字符到(字符指针)

Question

我如何将其转换为返回 char* 而不是使用 std::string 只想学习其他没有 std::string 的方法

string getName(DWORD Address)
{
    DWORD BaseDword = ReadBaseDword(Address);

    int size = ReadCharSize();

    string name = "";

    for (int i = 0; i < size - 1; i++)
    {
        char c = ReadCharArrayChar(i);
        name += c;
    }

    return name;
}

Answer 1

其他方式很丑陋，这是 std::string 存在的原因之一:)。但出于教育目的，这里是您如何返回 char*(按要求):

// caller is responsible for deleting the return value
char* getEntityName(DWORD Address)
{
    DWORD BaseDword = ReadBaseDword(Address); // (not sure what this achieves)

    int size = ReadCharSize();

    char* name = new char[size];
    name[size - 1] = '\0';

    for (int i = 0; i < size - 1; i++)
    {
        char c = ReadCharArrayChar[i](); // odd looking, but I'll assume this works
        name[i] = c;
    }

    return name;
}

类似的选项仍然使用缓冲区的原始指针，但调用者将其传入(连同其大小):

// returns: true iff the buffer was successfully populated with the name
// exceptions might be a better choice, but let's keep things simple here
bool getEntityName(DWORD Address, char* buffer, int maxSize)
{
    DWORD BaseDword = ReadBaseDword(Address); // (not sure what this achieves?)

    int size = ReadCharSize();
    if(size > maxSize)
       return false;

    buffer[size - 1] = '\0';

    for (int i = 0; i < size - 1; i++)
    {
        char c = ReadCharArrayChar[i](); // odd looking, but I'll assume this works
        buffer[i] = c;
    }

    return true;
}

后一个选项将允许，例如:

char buffer[100];
getEntityName(getAddress(), buffer, 100);