c - 如何从 10 个字符串的数组中打印 5 个唯一的字符串

Question

我正在编写一个代码，该代码将从 10 个字符串的数组中打印 5 个唯一且随机的字符串。但是我的代码并没有唯一地打印它，总是有一些重复。 这是我的代码，任何人都可以建议如何使其打印唯一吗？

#include<stdio.h>
#include<stdlib.h>
#include<math.h>




void main(void){
    char arr[10][10]={"abc","def","ghi","klm","nop","qrs","tuv","wxy","zab","cde"};
    int i=0,j=0;

    srand(time(0));

    for(i=0;i<5;i++){

    j=rand()%10;
    printf("%d\n",j);

    }
}

Answer 1

只记住已经打印出来的idices:

#include <stdio.h>
#include <stdlib.h>
#include <math.h>

int main()
{
    char arr[10][10] = {"abc","def","ghi","klm","nop","qrs","tuv","wxy","zab","cde"};
    int i = 0, j = 0;
    int done[10] = { 0 };

    srand(time(0));

    for (i = 0; i < 5; ++i)
    {
        do
        {
            j = rand()%10;
        }
        while (done[j] == 1);
        done[j] = 1;
        printf("%s\n", arr[j]);
    }

    return 0;
}