过去 5 个小时我一直坐在这里试图解决这个问题。我是 C 编程的新手。
我需要能够比较 for 循环中的值并存储它们，最后打印出哪个商店的价格最便宜以及相关的商店 #。这是我所拥有的，它一直给我奇怪的输出并且没有正确地添加订单:
#include <stdio.h>
int main() {
int shops = 0, ingredients = 0, i=0, j=0, cstore=0;
double temp = 0.0, ingredientPrice = 0.0, total, cprice=0.0;
printf("How many shops will you be visiting?\n");
scanf("%d",&shops);
for(i = 0; i < shops; i++){
printf("You are at shop # %d\n",i+1);
printf("How many ingredients do you need at shop #%d?\n", i+1);
scanf("%d",&ingredients);
for(j = 0; j < ingredients; j++) {
printf("How much is ingredient #%d?\n", j+1);
scanf("%lf", &temp);
ingredientPrice += temp;
total = ingredientPrice;
if (shops == 1) {
cstore = shops;
cprice = total;
}
else if(total < ingredientPrice) {
cstore = i+1;
cprice = total;
}
}
printf("Your total at shop #%d is $%lf\n", i+1, total);
}
printf("Your cheapest order was at shop #%d and cost $%lf.\n", cstore, cprice);
return 0;
}
作为旁注，不能使用数组，因为我们还没有讨论那一章。任何帮助将不胜感激!请和谢谢
如果有人需要弄清楚我在问什么，这里还有作业:
您的导师指派您去几家不同的商店下订单。该程序应询问将访问的商店总数。在每个商店，询问需要购买的食材数量。对于每种成分，询问价格。跟踪订单总额，以便您可以在离开商店之前记下来。这个程序 还应该跟踪订单是最便宜的，以及最便宜的订单在哪家商店。这将帮助您的导师决定继续与谁做生意!
输入规范 1.店铺数量为正整数。 2. 配料数量为正整数。 3.每种食材的成本都是正实数。
输出规范 输出每个店铺的成本，保留两位小数。
您在#Y 的总金额为 $X.XX。
程序结束时，打印最便宜的订单。
您最便宜的订单是在 #Y 商店订购的，价格为 $X.XX。
输出样本
您将参观多少家商店？ 3个 你在 1 号店。 1 号店需要多少原料？ 2个 成分#1 多少钱？ 3.5 配料#2 多少钱？ 10 您在 1 号店的总价是 13.50 美元。 你在 2 号店。 2 号店需要多少原料？ 3个 成分#1 多少钱？ 2.75 配料#2 多少钱？ 3个 #3 的成分是多少？ 1.25 您在 2 号店的总价是 7.00 美元。 你在 3 号店。 3 号店需要多少原料？ 2个 成分#1 多少钱？ 4个 配料#2 多少钱？ 5个 您在 3 号商店的总价是 9.00 美元。 您最便宜的订单是在 2 号商店订购的，价格为 7.00 美元。
最佳答案
阅读这个可能的解决方案。我没有费心去检查 scanf() 的返回值，但后来我很懒惰，无论如何都不将它用于生产代码。
#include <stdio.h>
int main() {
int i = 0, shops = 0;
int cstore = 0; // current minimum store
double cprice = 0.0; // total for the current minimum store
printf("How many shops will you be visiting?\n");
scanf("%d", &shops);
for (i = 1; i <= shops; i++){
int j = 0, ingredients = 0;
double total = 0.0; // total for the current store.
printf("You are at shop # %d\n", i);
printf("How many ingredients do you need at shop #%d?\n", i);
scanf("%d", &ingredients);
// get the prices of the ingredients at this store and total them up.
for (j = 1; j <= ingredients; j++) {
double ingredientPrice = 0.0;
printf("How much is ingredient #%d?\n", j);
scanf("%lf", &ingredientPrice);
total += ingredientPrice;
}
if (i == 1) {
// this is the first store so it is automatically the lowest thus far being the only one.
cstore = i;
cprice = total;
}
else if (total < cprice && ingredients > 0) {
// the total for this store is less than the last known smallest total so lets update our variables.
// if there are zero ingredients from this store then it does not count.
cstore = i;
cprice = total;
}
// the currency is US dollars with two decimal places.
printf("Your total at shop #%d is $%.2lf and the lowest store is %d for $%.2lf.\n", i, total, cstore, cprice);
}
printf("Your cheapest order was at shop #%d and cost $%.2lf.\n", cstore, cprice);
return 0;
}
我得到了这个输出。
How many shops will you be visiting?
3
You are at shop # 1
How many ingredients do you need at shop #1?
2
How much is ingredient #1?
3
How much is ingredient #2?
4
Your total at shop #1 is $7.00 and the lowest store is 1 for $7.00.
You are at shop # 2
How many ingredients do you need at shop #2?
3
How much is ingredient #1?
1
How much is ingredient #2?
3
How much is ingredient #3?
4
Your total at shop #2 is $8.00 and the lowest store is 1 for $7.00.
You are at shop # 3
How many ingredients do you need at shop #3?
3
How much is ingredient #1?
1
How much is ingredient #2?
2
How much is ingredient #3?
2
Your total at shop #3 is $5.00 and the lowest store is 3 for $5.00.
Your cheapest order was at shop #3 and cost $5.00.
关于C 编程 : Saving value in for loop and finding minimum，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/42183063/