标签 javascript arrays
<分区>
$('button').click(function () {
[1, 2, 3, 4, 5].forEach(function (n) {
if (n == 3) {
// it should break out here and doesn't alert anything after
return false
}
alert(n)
})
})<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<button>Click me</button>我的问题:为什么在我调用 return 时它仍然提醒下一个号码？就像:忽略下面的代码并继续下一个元素
最佳答案
There is no way to stop or break a
forEach()loop other than by throwing an exception. If you need such behavior, theforEach()method is the wrong tool.Early termination may be accomplished with:
- A simple loop
- A
for...ofloopArray.prototype.every()Array.prototype.some()Array.prototype.find()Array.prototype.findIndex()The other Array methods:
every(),some(),find(), andfindIndex()test the array elements with a predicate returning a truthy value to determine if further iteration is required.
关于javascript - `return` 关键字在 `forEach` 函数中意味着什么？，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/34653612/