C指向结构中数组的指针传递给函数

Question

我正在尝试将指向数组的指针传递到结构内部的回调函数中以进行 sqlite3 操作。不幸的是，基于我对指针的理解(显然遗漏了一些东西)的逻辑不起作用。

简化了，这就是我所拥有的:

    typedef struct sqlCallbackData
    {
        int16_t data_array[128][32];

        // There are other members here too...

    } SqlCallbackData_t;

    //===========================================================================================================
    //===========================================================================================================

    void sql_getData(uint8_t seq_num, uint8_t seq_bank, int16_t *data, char *name)
    {
        // 'data' above will be a pointer to a 2D array

        //...

        // Initialise struct members to be passed into callback...
        SqlCallbackData_t paramStruct;

        //Thows: error: incompatible types when assigning to type 'int16_t[128][32]' from type 'int16_t *'
        paramStruct.data_array = data;// I know this isn't right...

        //...

        // Pointer to paramStruct passed into void pointer in callback...
        if (sqlite3_exec(dbPtr, sql, callback, &paramStruct, &zErrMsg) != SQLITE_OK)
        {
            fprintf (stderr, "SQL error: %s\r\n", zErrMsg);
            sqlite3_free(zErrMsg);
        }

        //...
    }

    //===========================================================================================================
    //===========================================================================================================
    // Callback function

    static int load_callback(void *paramStruct, int argc, char **argv, char **azColName)
    {
        int i;

        uint8_t value;

        //...

        // Just making the syntax below a bit mroe readable, as I access members a fair bit in this function
        SqlCallbackData_t *params = ((SqlCallbackData_t *)paramStruct);

        //...
        // Data retreived from sql database...

        params->data_array[0][0] = value;// <- What I'm trying to acheive...obviosuly not correct

        return 0;
    }

所以我知道指向数组的指针是如何传递给函数的(解释为 here )，但是我对如何将这个指向数组的指针分配给结构、传递给函数(然后再次作为数组访问)。

绕圈子，所以任何帮助将不胜感激:)

Answer 1

I am trying to pass a pointer to an array, inside a structure

为此你需要像这样改变结构，看看two dimensional array pointer

typedef struct sqlCallbackData
{
     int16_t (*data_array)[32]; //2d array pointer

    // There are other members here too...

} SqlCallbackData_t;

当您将地址分配给指针时...

void sql_getData(uint8_t seq_num, uint8_t seq_bank, int16_t (*data)[32], char *name)
    {
        // 'data' above will be a pointer to a 2D array
        // Initialise struct members to be passed into callback...
        SqlCallbackData_t paramStruct;

        paramStruct.data_array = data;