c - 如何初始化在 typdef union 中深埋 2 层的 int

Question

我想执行以下操作

static Type2 MyData;
MyData.Base.Data = (0b0000000000010100);

作为静态初始化。例如

static Type2 MyData = (typecast)(0b0000000000010100);

我会用什么来打字？ 这是 Type1 和 Type2 的类型定义

typedef union
{
    UINT16 Data;
    struct
    {
        unsigned      :10;  
        unsigned var1 :3;   
        unsigned var2 :2;   
        unsigned var3 :1;   
    };
} Type1;    

typedef union
{
    Type1 Base;     
    struct
    {
        unsigned var4 :3;
        unsigned var5 :2;   
        unsigned      :11;
    } Data;
} Type2;

Answer 1

类似于this question ，尝试 Type2 t = { .Base.Data = 0x18 }; 如果您的目标是在 Type1 中设置位域，您应该直接调用它们；见here .