在循环中收集字符串并打印出循环外的所有字符串

Question

我是新手，有一些问题想请教大家。 例如:

#include <stdio.h>
#include<stdlib.h>
#include<ctype.h>

void main()
{
    char name[51],selection;

    do
    {

    printf("Enter name: ");
    fflush(stdin);
    fgets(name,51,stdin);
    printf("Enter another name?(Y/N)");
    scanf("%c",&selection);
    selection=toupper(selection);
    }while (selection=='Y');
                     //I want to printout the entered name here but dunno the coding
printf("END\n");
system("pause");
}

据我所知，循环执行何时会覆盖变量，那么我如何执行编码以打印出用户输入的所有名称？ 我已经问过我的导师，他让我使用指针，这种情况下谁能指导我？

Answer 1

您基本上有两个选择，创建一个包含所有名称的列表，在最后遍历每个名​​称，或者在您读取它们时将所有名称连接成一个字符串，并在最后打印整个缓冲区。第一个大致是这样的:

 char ch[2]="Y", names[100][52]; //store up to 100 50-char names (leaving space for \n and \0)
 int x, nnames=0;
 while(nnames<100 && *ch=='Y'){
     fgets(names[nnames++], sizeof names[0], stdin); //since names is a 2d array, look
     //only at the length of a row, (in this case, names[0])
     fgets(ch, 2, stdin);
     *ch = toupper(*ch);
 }
 for(x=0; x<nnames; x++)
     //print names[x].

第二个大致是这样的:

 char names[100*52], *np=names, *ep=names+sizeof names; //an array, the position, and the end
 char ch[2]="Y";
 while(np<ep && *ch=='Y'){
      fgets(np, ep-np, stdin); //read a name, and a newline into the buffer
      //note how I use the difference between the end and the position to tell
      //fgets the most it can possibly read
      np+=strlen(np); //advance the position to the end of what we read.
      //same deal with the y/n stuff...
 }
 printf("%s", names);

注意最后没有循环，因为整个字符串都存储在名称中。