c - 获取退出代码总是返回 1

Question

我正在从事一个包含线程和进程的项目。我打开多线程，并为每个线程打开一个运行 exe 文件的进程。 如果程序以非 0 的返回值结束，它就会崩溃，并且应该打印返回值。为了获得返回值，我使用 WIN API 函数 GetExitCodeProcess() 我的问题是这个函数总是返回值 1，即使程序应该崩溃，但为什么呢？ 这是我的相关代码:

static DWORD WINAPI RunningTests(test_s *test)
{
    PROCESS_INFORMATION procinfo;
    DWORD waitcode;
    DWORD exitcode;
    int status = 0, crashed = 0;
    char cmdLineString[MAX_NUMBER_OF_CHARS_IN_CMD_LINE]="";
    char *cmdLineStringPtr = cmdLineString;

    (test)->isCrashed = 0;
    CreateCmdLine((*test).testExePath, &cmdLineStringPtr);
    status = CreateProcessSimple(_T(cmdLineString), &procinfo);
    if (status == -1)
    {
        return 1;
    }
    waitcode = WaitForSingleObject(procinfo.hProcess, 
    TIME_UNTIL_TIMED_OUT_IN_MILLISEC);
    if (waitcode == WAIT_TIMEOUT) /* Process is still alive */
    {
        strcpy((*test).status, "Timed Out");
        CloseHandle(procinfo.hProcess);
        CloseHandle(procinfo.hThread);
        return 0;
    }
   crashed = GetExitCodeProcess(procinfo.hProcess, &exitcode);
   if (crashed == 0)  /* Process is crashed */
   {
        strcpy((*test).status, "Crashed");
        (*test).isCrashed = 1;
        (*test).returnedCrashedValue = exitcode;
        CloseHandle(procinfo.hProcess);
        CloseHandle(procinfo.hThread);
        return 0;
    }
    CloseHandle(procinfo.hProcess);
    CloseHandle(procinfo.hThread);
    return CompareFiles(&test);              
}

Answer 1

您应该查看退出代码，而不是崩溃；

Return Value

If the function succeeds, the return value is nonzero.

If the function fails, the return value is zero. To get extended error information, call GetLastError.