我有以下 C 代码:
int main(int argc, char* argv[])
{
CURL *curl;
CURLcode res;
struct stat file_info;
double speed_upload, total_time;
FILE *fd;
fd = fopen(argv[1], "rb"); /* open file to upload */
if(!fd) {
return 1; /* can't continue */
}
/* to get the file size */
if(fstat(fileno(fd), &file_info) != 0) {
return 1; /* can't continue */
}
curl = curl_easy_init();
if(curl) {
/* upload to this place */
curl_easy_setopt(curl, CURLOPT_URL,
"http://www.website.com/index.php");
/* tell it to "upload" to the URL */
curl_easy_setopt(curl, CURLOPT_POST, 1L);
/* set where to read from (on Windows you need to use READFUNCTION too) */
curl_easy_setopt(curl, CURLOPT_READDATA, fd);
/* and give the size of the upload (optional) */
curl_easy_setopt(curl, CURLOPT_INFILESIZE_LARGE,
(curl_off_t)file_info.st_size);
/* enable verbose for easier tracing */
curl_easy_setopt(curl, CURLOPT_VERBOSE, 1L);
res = curl_easy_perform(curl);
/* Check for errors */
if(res != CURLE_OK) {
fprintf(stderr, "curl_easy_perform() failed: %s\n",
curl_easy_strerror(res));
}
else {
/* now extract transfer info */
curl_easy_getinfo(curl, CURLINFO_SPEED_UPLOAD, &speed_upload);
curl_easy_getinfo(curl, CURLINFO_TOTAL_TIME, &total_time);
fprintf(stderr, "Speed: %.3f bytes/sec during %.3f seconds\n",
speed_upload, total_time);
}
/* always cleanup */
curl_easy_cleanup(curl);
}
return 0;
}
和以下 PHP 代码:
<?php
header('Access-Control-Allow-Origin: *');
if ($_SERVER['REQUEST_METHOD'] == 'POST' )
{
if( isset( $_FILES["file_entry"] ) )
{
print "file ok";
}
else
{
print "no file sent";
}
}
else
{
print "No post method" . $_SERVER['REQUEST_METHOD'];
}
?>
和html代码:
<!DOCTYPE html>
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8">
<title></title>
</head>
<body>
<form action="index.php" enctype="multipart/form-data" method="post">
<input type="file" name="file_entry"/>
<input type="submit" value="enviar"/>
</form>
</body>
</html>
如果我尝试通过 html 发送文件，它工作正常，但当我使用 C 和 cURL 时就不行了。 因为我不知道如何发送“file_entry”。我怎样才能像 html 那样用 C cURL 模拟提交“file_entry”？我尝试使用 CURLOPT_POSTFIELDS，但不起作用。
谁能帮帮我？
谢谢
最佳答案
这是因为您的服务器端需要一个“multipart/form-data”POST，而您发送了一个常规的“url-encoded”POST。
例如，您应该查看 multi-post.c示例或 curl_formadd () 文档。
或者您更改服务器端。
关于php - 使用 POST 使用 curl 上传文件，但模拟 HTML 提交，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/14570880/