无法将字符串分配给结构内的指针

Question

这是我的一段代码，我试图让它变得更简单，我试图将一个字符串分配给数组内结构内的指针，我还想将指针初始化为 NULL，以便我可以检查是否或者不是已经有医生在使用这个房间了...... 我不断收到段错误错误 我将不胜感激任何帮助

struct appointment{
    char *SSN;
    int status;//is appointment already taken?
};

struct room{
    int doctorID;
    char *doctorname;
    struct appointment hours[10];
};

struct room clinic[5];

for(int i = 0; i < 5; i++){    //I was trying to initialize all pointers to NULL but didn't work
    clinic[i].doctorID = 0;
    for(int j = 0; i < 10; i++){
        clinic[i].hours[j].status = 0;
    }
}

for(int i = 0; i < 5; i++){
    clinic[i].doctorname = malloc(sizeof(char) * 30); // Am I doing something wrong here?
    *clinic[i].doctorname = "fernando";
    printf("the name of the doctor on clinic %d is %s\n", i, clinic[i].doctorname
    free(consultorios[i].medico);
    }
return 0;
}

Answer 1

如果您想分配一个字符串用户strcpy。

更改线路

*clinic[i].doctorname = "fernando";

至

strcpy(clinic[i].doctorname, "fernando");