golang make struct T implement I 但不是 *T

Question

我有一个实现接口(interface) I 的结构 T，但我希望 *T 不实现该接口(interface)。这可能吗？

也就是说，这应该可以正常编译:

var obj I = T{}

但这会产生一个编译错误:

var obj I = &T{}

原因是我的代码库中的一个常见错误是在预期只会使用 T 时意外使用 *T 作为某个接口(interface) I。

Answer 1

不可能。来自spec (强调我的):

A type may have a method set associated with it. The method set of an interface type is its interface. The method set of any other type T consists of all methods declared with receiver type T. The method set of the corresponding pointer type *T is the set of all methods declared with receiver *T or T (that is, it also contains the method set of T).