c++ - 如何打印以筛选结构及其所有内容？

Question

我想在 c/c++ 中找到一个宏，它获取结构 typedef 和一个指向结构的指针作为输入并打印所有它的内容是这样的:

假设我有一个名为 struct account 的结构。

struct account {
   int account_number;
   char *first_name;
   char *last_name;
   float balance;
};

我这样使用它:

struct account my_account= {    
    .account_number = 321321,
    .first_name = 0x12345678,
    .last_name = 0,
    .balance = 222 };

我想要在 linux 内核/c 语言中有一个看起来像这样的宏:

PRINT_STRUCT_CONTENT(struct_type, pointer)

并打印以下内容:

my_account= {
account_number = 321321,
first_name = 0x12345678,
last_name = 0,
balance = 222
}

想法是在内核中有一种 dir python 函数

---

Write a Macro to stringify the contents of a struct

Your most general C macro for printing variable values in different types

Is there a C preprocessor macro to print out a struct?

Writing a while loop in the C preprocessor

Answer 1

您可以使用 print_hex_dump或 print_hex_dump_bytes
示例:

struct mystruct *p;
print_hex_dump_bytes("mystruct: ", DUMP_PREFIX_ADDRESS, p, sizeof(*p));