我用 FORTRAN 90 编写了一个小型测试用例程序,它初始化切片中的 3d 数组。可以在 C 语言中轻松复制相同的行为吗?
program fortranEngine
real(4) , dimension(10,10) :: tmp
real(4) , dimension(10,10,3) :: p
tmp = RESHAPE( [ 0.973, 1.053, 0, 0, 0, 0, 0, 0, 0, 0, &
1.053, 1.080, 0, 0, 0, 0, 0, 0, 0, 0, &
1.010, 0.408, 0.442, 0, 0, 0, 0, 0, 0, 0, &
1.119, 0.900, 0.399, 0.762, 0, 0, 0, 0, 0, 0, &
1.211, 0.975, 0.845, 0.952, 1.105, 0, 0, 0, 0, 0, &
1.248, 1.016, 0.485, 0.000, 0.000, 1.110, 0, 0, 0, 0, &
1.225, 1.123, 1.056, 0.000, 0.000, 0.949, 0.832, 0, 0, 0, &
1.138, 1.232, 1.089, 1.050, 0.930, 0.402, 0.789, 0.774, 0, 0, &
1.149, 1.406, 1.201, 1.052, 0.416, 0.878, 0.896, 0.431, 1.144, 0, &
1.351, 1.255, 1.290, 1.358, 1.240, 1.228, 1.257, 1.140, 1.123, 1.228] &
, [10,10] )
p(:,:,1) = tmp
...
end program fortranEngine
最佳答案
您或多或少可以在 C99 或 C2011 中执行此操作,但不如在 Fortran 中方便。当心initialization命令; Fortran 以一种顺序(列优先)执行,C 以另一种顺序(行优先)执行。忽略它,你可以这样做:
float tmp[10][10] =
{
{ 0.973, 1.053, 0, 0, 0, 0, 0, 0, 0, 0, },
{ 1.053, 1.080, 0, 0, 0, 0, 0, 0, 0, 0, },
{ 1.010, 0.408, 0.442, 0, 0, 0, 0, 0, 0, 0, },
{ 1.119, 0.900, 0.399, 0.762, 0, 0, 0, 0, 0, 0, },
{ 1.211, 0.975, 0.845, 0.952, 1.105, 0, 0, 0, 0, 0, },
{ 1.248, 1.016, 0.485, 0.000, 0.000, 1.110, 0, 0, 0, 0, },
{ 1.225, 1.123, 1.056, 0.000, 0.000, 0.949, 0.832, 0, 0, 0, },
{ 1.138, 1.232, 1.089, 1.050, 0.930, 0.402, 0.789, 0.774, 0, 0, },
{ 1.149, 1.406, 1.201, 1.052, 0.416, 0.878, 0.896, 0.431, 1.144, 0, },
{ 1.351, 1.255, 1.290, 1.358, 1.240, 1.228, 1.257, 1.140, 1.123, 1.228 },
};
float p[3][10][10];
for (int i = 0; i < 3; i++)
memmove(p[i], tmp, sizeof(tmp));
请注意,虽然我将维度 [3]
从声明的末尾移到了声明的开头。另一种方式在 C 中没有多大意义。因此,该表示法或多或少可用,但存储管理的细节使得如何准确实现您想要的不太明显。
关于c - C中初始化多维数组类似于Fortran,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/15411041/