c - 扫描字符然后在 IF 语句中使用它们？ (如果 char= ='c' ){} 等

Question

到目前为止我的代码:

#include <stdio.h>

main() 
{
    float p_Asphalt = 5.2, p_Concrete = 4.93, p_Stones = 2.21;
    float c_Concrete = 8.88; 
    float d_Length =, d_Width;
    char typeOfPaving, c_Curbing;
    float totalCost = 0;
    float GST = 1.13, PST = 1.10;

    printf("asphalt company\n\n");
    printf("Length of Driveway: ");
        scanf("%f", &d_Length);
    printf("Width of Driveway: ");
        scanf("%f", &d_Width);
    printf("\nType of Paving:\n");
    printf(" 'A' for asphalt paving\n");
    printf(" 'C' for concrete paving\n");
    printf(" 'S' for paving stones\n\n");
    printf("Select (A,C,S): ");
        scanf("%c%c", &typeOfPaving);
    printf("%c", typeOfPaving);

    if (typeOfPaving == "A") 
    {
        totalCost = p_Asphalt * (d_Length * d_Width);
        printf("Concrete curbing? [y/n]: ");

            scanf("%c%c", c_Curbing);

            if (c_Curbing == 'y') { 
                totalCost = totalCost + (d_Length * c_Concrete);
            }
            else {
                totalCost = totalCost * GST;
                printf("Quoted Price of Paving: %f\n", totalCost);
            }
    } 
    else if (typeOfPaving == "C") 
    {
        totalCost = p_Concrete * (d_Length * d_Width);
        printf("Quoted Price of Paving: %f\n", totalCost);
    } 
    else if (typeOfPaving == "S") 
    {
        totalCost = p_Stones * (d_Length * d_Width);
        printf("Quoted Price of Paving: %f\n", totalCost);
    }
}

出于某种原因，当我编译时，我得到以下输出:

:~/> cc assignment1.c ^C
:~/>
:~/> a.out
asphalt company

Length of Driveway: 123
Width of Driveway: 123

Type of Paving:
 'A' for asphalt paving
 'C' for concrete paving
 'S' for paving stones

Select (A,C,S): A

:~/>

没有任何反应。在我有 scanf("%c%c", &typeOfPaving); 的第 22 行，我使用 %c%c 因为我的教授告诉我第一个 %c 存储输入数据后的换行符进入第 16 行的变量 d_Width:scanf("%f", &d_Width);。我现在看到的问题是(我认为？)char typeOfPaving 存储\nA？不只是 A 所以我的 if 语句不起作用？对吗？

谁能帮帮我，不知道该怎么办，哈哈，有点沮丧

Answer 1

"C" 是一个char 数组，'C' 是一个char。这就是您可能需要的:

if (typeOfPaving == 'C')