c - C中使用realloc的动态内存分配

Question

我已经阅读了关于使用 realloc 获取指向更大内存地址空间开头的新指针的其他 SO 问题，但我无法弄清楚我做错了什么。它打印回溯和内存转储。稍后我尝试访问 strhldr，但我认为它甚至无法访问那么远。

char *strhldr = (char *)malloc(strsize);

 int chrctr = 0;
 if(chrctr == strsize - 3){ // when you get close
  strsize = strsize*2; //double size
  char *temp = realloc(strhldr, strsize); //make more room
    if(temp == NULL)
     printf("reallocate failed\n");
    else{
     strhldr = temp;
     free(temp); // removed same issue
    }
} 

// Later attempt to add it to an array
cmdargs[i] =  strhldr;

这一切都在一个 while 循环中，其中 chrctr 和 strsize 递增

完整代码

  int argctr = 64;
  char **cmdargs = (char **) malloc(argctr * sizeof(char*));
  char c = getchar();
  int i = 0;


  while(c != '\n' && c != EOF){ //read through a String of stdin
  int strsize = 32;
  char *strhldr = (char *)malloc(strsize);
  char *strstarthldr = strhldr;


    if(c == ' ')
      c = getchar();
    while(c != ' ' && c != '\n' && c != EOF){

      int chrctr = 0;
     if(chrctr == strsize - 3){ // when you get close
      strsize = strsize*2; //double size
      char *temp = realloc(strhldr, strsize); //make more room
        if(temp == NULL)
         printf("reallocate failed\n");
        else
         strhldr = temp;

    }      //add that word to the array of strings
      strhldr[chrctr] = c;
      chrctr++;
      c = getchar();

    }
    strhldr[charctr] = '\0';
    //strhldr = strstarthldr;
    cmdargs[i] =  strhldr;
    i++;
  }

Answer 1

成功时，realloc 将在需要时释放它的参数。所以删除对 free(temp) 的调用。