c - 错误 : format %d expects type int, 但参数 2 的类型为 double(*)(int, int)

Question

我似乎无法在我的 printf 语句中找出这个错误。每当我将格式说明符从整数更改为 float ，反之亦然时，我只会遇到相同的错误。

     error: format â%fâ expects type âdoubleâ, but argument 2 has type âdouble (*)(int,     int)â

这是我的代码中的那部分

void outputScores(int x, int y)
{
if(((x&y)>=1) && ((x&y)<=20))
{
printf("------------------------------\n");
printf("\n");
printf("Field: %d,%d\n",x,y);
printf("\n");
printf("Soil quality: %f\n",soilQuality);
printf("Sun exposure: %d\n",sunExposure);
printf("Irrigation exposure: %d\n",irrigationExposure);
printf("\n");
printf("Estimated yield: %d\n",estimatedYield);
printf("Estimated quality: %d\n",estimatedQuality);
printf("Time to harvest: %d\n",harvestTime);
printf("\n");
printf("Overall Score: %f\n",fieldScore);
printf("\n");
printf("------------------------------\n");
}
else
{
printf("Field %d, %d is invalid!\n",x,y);
}
return;
}

这是函数

 double soilQuality(int x, int y)
 {
 if((x>=1) && (x<=20) && (y>=1) && (y<=20))
 {
 if((x+y)%2==1)
 {
 int soilQuality=(1+(sqrt((x-10)*(x-10))+((y-10)*(y-10))));
 return soilQuality;
 }
 else
 {
 int soilQuality=(1+((abs(x-10)+abs(y-10))/2));
 return soilQuality;
 }
 }
 else
 {
 return -1;
 }
 }

Answer 1

在 printf() 中，%f 期望一个 double，但是您给它一个指向 double 类型函数的指针(*)(int, int).

所以改变

printf("Soil quality: %f\n",soilQuality);

到

printf("Soil quality: %f\n",soilQuality(x, y));

再试一次。