我有以下 struct
,它具有可以更新其字段的功能:
type Dog struct {
name string
age int
}
func (dog *Dog) growOld() {
dog.name = "old dog"
dog.age++
}
以上内容单独运行良好。但是,当 struct
属于另一个对象并且该对象告诉 struct
更新其字段时,更改似乎发生但未应用:
package main
import (
"fmt"
)
type Owner struct {
dog Dog
}
func newOwner(dog Dog) Owner {
var owner Owner
owner.dog = dog
return owner
}
func (owner Owner) tellDogToGrowOld() {
owner.dog.growOld()
}
func main() {
var dog Dog
dog.name = "dog"
owner := newOwner(dog)
owner.tellDogToGrowOld()
fmt.Println(dog) // dog's name is still `dog` and age is 0.
}
我假设我必须以某种方式使用指针
,但不太清楚如何。
最佳答案
如果您希望该方法修改接收者的状态,则该方法的接收者类型应该是指针类型。
也就是说,与声明growOld
方法的方式相同,tellDogToGrowOld
方法也应该有一个指针接收器:
func (owner *Owner) tellDogToGrowOld() {
owner.dog.growOld()
}
或者,您可以将要修改的字段设为指针,例如:
type Owner struct {
dog *Dog
}
func newOwner(dog *Dog) Owner {
var owner Owner
owner.dog = dog
return owner
}
func (owner Owner) tellDogToGrowOld() {
owner.dog.growOld()
}
关于go - 当另一个对象告诉结构更新时结构字段不更新,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/55236767/