c - ‘{’ token c 程序之前的预期表达式

Question

我写了下面的代码我在编译这部分代码时正在解决一个难题

#include <stdio.h>
int main ()
{

int a[10],b[10],c[10];
int i,j,k,l;
 a[10]={"21","33","12","19","15","17","11","12","34","10"};
 b[10]={"10","15","9","13","16","21","15","32","29","7"};
 c[10]={"11","8","3","6","1","4","6","20","19","3"};

 l=sizeof(a)/sizeof(a[0]);

for (i=0;i<=l;i++)
 {
 }
}

给我错误

array.c: In function ‘main’:
array.c:7:8: error: expected expression before ‘{’ token
array.c:8:8: error: expected expression before ‘{’ token
array.c:9:8: error: expected expression before ‘{’ token

为什么错误会出现在这里？

Answer 1

您的代码中存在几个问题:

1. 您应该在声明它们的同一行中初始化您的数组
2. 您必须使用数字数组而不是 C 字符串数组来初始化它们:
3. 您实际上尝试将值设置为数组的第 11 个元素。

正确的代码行是:

int a[10] = {21,33,12,19,15,17,11,12,34,10};