我为 FCFS 调度编写了以下代码。
问题是这段代码编译正常,但是执行./a.out
后,什么也没有显示,程序卡住了。它甚至不打印 main()
开头的 "Reading"
printf
语句。有什么问题?
#include <stdio.h>
struct process
{
int at;
int bt;
int wt;
int tt;
int rt;
char pid[5];
} p[5];
int i, j;
int n = 0;
void main()
{
printf("Reading");
FILE *fp;
fp = fopen("in1.txt", "r");
char sample;
if (fp != NULL )
{
sample = getc(fp);
while (sample != EOF);
{
if (sample == '\n')
n++;
sample = getc(fp);
}
fseek(fp, 0, 0);
for (i = 0; i < n; i++)
{
fscanf(fp, "%s %d %d", p[i].pid, &p[i].at, &p[i].bt);
p[i].wt = p[i].tt = 0;
p[i].rt = p[i].bt;
}
fclose(fp);
}
//sorta();
printf("\nGantt Chart for FCFS\n");
int t = 0;
int avgw = 0;
int avgt = 0;
printf("%d ", t);
for (i = 0; i < n; i++)
{
if (p[i].at > t)
{
printf("%d ", t);
t = p[i].at;
}
p[i].wt = t - p[i].at;
avgw = avgw + p[i].wt;
printf("%s ", p[i].pid);
p[i].tt = p[i].bt + p[i].wt;
avgt = avgt + p[i].tt;
t = t + p[i].bt;
printf("%d ", t);
printf("\navg waiting time = %d", avgw / n);
printf("\navg turn around time = %d", avgt / n);
}
}
最佳答案
标准输出是行缓冲的。把“Reading”改成“Reading\n”,就可以看到了。
那你这里就错了:
while (sample!=EOF);
那个 while 循环的主体只是分号,而不是后面的 block !如果条件为真,您的程序将陷入无限循环。
关于C程序卡住,甚至不进入主程序,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/17358157/