我有两个轮廓 vector OUTERCONT 和 INNERCONT 在 openCV 中定义为 vector ( vector (点))。我想检查一个轮廓是否存在于另一个轮廓内。我还想知道每个 OUTERCONT 内存在多少个轮廓。 我目前正在每个轮廓周围绘制一个 minEnendingRect 并检查以下内容:
for (int i = 0; i < outerrect.size(); i++)
{
count = 0;
for (int j = 0; j < innerrect.size(); j++)
{
bool is_inside = ((innerrect[j] & outerrect[i]) == innerrect[j]);
if (is_inside == 1)
count++;
}
if (count > 0)
{
//DO SOMETHING
}
cout << count << endl;
这似乎不起作用,它总是将计数返回为 120 左右的某个数字,这是不正确的。您能否建议进行任何更改以使其正常工作?
注意:我无法使用层次结构,因为它们是从 2 个不同函数返回的两组独立的轮廓。
我知道 PointPloygon 测试是一种选择,但是您能建议更多的方法吗?
最佳答案
这是我从评论中得到的想法:
// stacked contours
int main(int argc, char* argv[])
{
cv::Mat input = cv::imread("C:/StackOverflow/Input/Contours_in_Contours.png");
cv::Mat input_red = cv::imread("C:/StackOverflow/Input/Contours_in_Contours_RED.png");
cv::Mat reds;
cv::inRange(input_red, cv::Scalar(0, 0, 200), cv::Scalar(50, 50, 255), reds);
std::vector<std::vector<cv::Point> > contours1;
cv::findContours(reds, contours1, CV_RETR_EXTERNAL, CV_CHAIN_APPROX_NONE);
cv::Mat input_yellow = cv::imread("C:/StackOverflow/Input/Contours_in_Contours_YELLOW.png");
cv::Mat yellows;
cv::inRange(input, cv::Scalar(0, 200, 200), cv::Scalar(0, 255, 255), yellows);
std::vector<std::vector<cv::Point> > contours2;
cv::findContours(yellows, contours2, CV_RETR_EXTERNAL, CV_CHAIN_APPROX_NONE);
// now we have 2 sets of contours and want to find out whether contours of set2 are completely within a contour of contours1 without hierarchy information.
std::vector<cv::Mat> masks1;
std::vector<int> nMaskPixels1;
// for each contour in contours1: create a contour mask:
for (int i = 0; i < contours1.size(); ++i)
{
cv::Mat mask1 = cv::Mat::zeros(input.size(), CV_8UC1);
cv::drawContours(mask1, contours1, i, cv::Scalar::all(255), -1); // draw filled
int nPixel1 = cv::countNonZero(mask1);
masks1.push_back(mask1);
nMaskPixels1.push_back(nPixel1);
}
std::vector<cv::Mat> masks2;
std::vector<int> nMaskPixels2;
// for each contour in contours2: test whether it is completely within the reference contour:
for (int j = 0; j < contours2.size(); ++j)
{
cv::Mat mask2 = cv::Mat::zeros(input.size(), CV_8UC1);
cv::drawContours(mask2, contours2, j, cv::Scalar::all(255), -1); // draw filled
int nPixel2 = cv::countNonZero(mask2);
masks2.push_back(mask2);
nMaskPixels2.push_back(nPixel2);
}
for (int i = 0; i < masks1.size(); ++i)
{
cv::Mat mask1 = masks1[i];
// draw mask again for visualization:
cv::Mat outIm = input.clone();
cv::drawContours(outIm, contours1, i, cv::Scalar(0, 0, 0), 3);
for (int j = 0; j < masks2.size(); ++j)
{
cv::Mat mask2 = masks2[j];
cv::Mat overlap = mask1 & mask2;
int nOverlapPixels = cv::countNonZero(overlap);
if (nOverlapPixels == 0) continue; // no overlap at all. Test next contour.
if (nOverlapPixels == nMaskPixels2[j] && nOverlapPixels < nMaskPixels1[i])
{
// second contour is completely within first contour
cv::drawContours(outIm, contours2, j, cv::Scalar(0, 255, 0), 3);
}
else if (nOverlapPixels == nMaskPixels2[j] && nOverlapPixels == nMaskPixels1[i])
{
// both contours are identical
std::cout << "WARNING: " << "contours " << i << " and " << j << " are identical" << std::endl;
}
else if (nOverlapPixels < nMaskPixels2[j] && nOverlapPixels == nMaskPixels1[i])
{
// first contour is completely within second contour
std::cout << "WARNING: " << "contour " << i << " of the first set is inside of " << j << std::endl;
}
else if (nOverlapPixels < nMaskPixels2[j] && nOverlapPixels < nMaskPixels1[i])
{
// both contours intersect
cv::drawContours(outIm, contours2, j, cv::Scalar(255, 0, 255), 3);
}
}
cv::imshow("contours", outIm);
cv::imwrite("C:/StackOverflow/Output/contours.png", outIm);
cv::waitKey(0);
}
cv::imshow("input", input);
cv::waitKey(0);
return 0;
}
此代码将从这两个图像创建两组轮廓:
计算轮廓掩模并比较它们。
结果将按轮廓显示。黑色轮廓是引用,绿色是完全在引用内的轮廓,紫色是相交轮廓。
我使用此图像来绘制结果:
得到这些结果:
轮廓1:
轮廓2:
如您所见,未检测到孤独的黄色轮廓与任何红色轮廓相交或包含在任何红色轮廓中。
关于c++ - 搜索一个轮廓是否存在于另一个轮廓内,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/37239872/