templates - Go:在模板文件中打印 URI(echo 框架)

Question

我正在使用 echo 框架。尝试将 URI :mynumber 打印为模板文件中的变量时，我卡住了。

除了 URI :mynumber 之外的所有变量都工作正常。我不知道如何将 :mynumber 与 Name & Age

一起包括在内

下面是我的server.go:

package main

import (
    "github.com/labstack/echo"
    "html/template"
    "io"
    "net/http"
)

type Person struct {
    Name, Age, Mynumber string
}

type (
    Template struct {
        templates *template.Template
    }
)

func (t *Template) Render(w io.Writer, name string, data interface{}) error {
    return t.templates.ExecuteTemplate(w, name, data)
}

func main() {
    e := echo.New()

    p := Person{Name: "Mike San", Age: "35"}

    t := &Template{
        templates: template.Must(template.ParseFiles("public/views/testhere.html")),
    }
    e.Renderer(t)

    e.Get("/testing/:mynumber", func(c *echo.Context) {
        c.Render(http.StatusOK, "onlytestingtpl", p)
    })

    e.Run(":4444")
}

下面是public/views/testhere.html:

{{define "onlytestingtpl"}}My name is {{.Name}}. I'm {{.Age}} years old. My number is {{.Mynumber}}.{{end}}

供您引用，下面是没有模板文件的打印 URI 示例:

package main

import (
    "github.com/labstack/echo"
    "net/http"
)

func main() {
    e := echo.New()

    e.Get("/users/:id", func(c *echo.Context) {
        id := c.Param("id")
        c.String(http.StatusOK, "My number is "+id)
    })

    e.Run(":4444")
}

Answer 1

您只需根据您的工作示例从 URL 中检索它:

number := c.Param("mynumber")

并将其设置在您传入的 Person 实例上:

p.Mynumber = number

这会导致:

e.Get("/testing/:mynumber", func(c *echo.Context) {
    number := c.Param("mynumber")
    p.Mynumber = number
    c.Render(http.StatusOK, "onlytestingtpl", p)
})