我正在使用 OpenCV 2.4.2
这是 OpenCV 文档中的引文
C++: void HoughLinesP(InputArray image, OutputArray lines, double rho, double theta, int threshold, double minLineLength=0, double maxLineGap=0 )
Parameters:
image – 8-bit, single-channel binary source image. The image may be modified by the function.
lines – Output vector of lines. Each line is represented by a 4-element vector , where and are the ending points of each detected line segment.
rho – Distance resolution of the accumulator in pixels.
theta – Angle resolution of the accumulator in radians.
threshold – Accumulator threshold parameter. Only those lines are returned that get enough votes().
minLineLength – Minimum line length. Line segments shorter than that are rejected.
maxLineGap – Maximum allowed gap between points on the same line to link them
我的问题是
minLineLength 和 maxLineGap 是以像素为单位测量的吗？或者什么？
最佳答案
翻阅旧的 Intel OpenCV 手册，您可以看到它将 LineLength 描述为 Pixels http://opencv.jp/opencv-1.0.0_org/docs/opencvman_old.pdf
It retrieves no more than linesNumber line segments; each of those must be not shorter than lineLength pixels.
像素在这里似乎是最合乎逻辑的。 Rho，累加器的距离分辨率定义为以像素为单位。
此处的示例显示使用的值为 30:
http://www.scribd.com/doc/77374092/155/cv-HoughLinesP
关于c# - HoughLinesP参数!单元？，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/14022385/