xml - 正确的结构布局以在 go 中解析 xml

Question

尝试使用 golang 解析一些 nmap 数据，但我的结构布局不太有效。链接到 Playground 上的代码:https://play.golang.org/p/kODRGiH71W

package main

import (
    "encoding/xml"
    "fmt"
)

type Extrareasons struct {
    Reason string `xml:"reason,attr"`
    Count  uint32 `xml:"count,attr"`
}

type Extraports struct {
    State  string       `xml:"state,attr"`
    Count  uint32       `xml:"count,attr"`
    Reason Extrareasons `xml:"extrareasons"`
}

type StateProps struct {
    State  string `xml:"state,attr"`
    Reason string `xml:"reason,attr"`
}

type PortProps struct {
    Protocol string `xml:"protocol,attr"`
    Port     uint32 `xml:"portid,attr"`
    StateStuff StateProps `xml:"state"`
}

type PortInfo struct {
    Extra    Extraports `xml:"extraports"`
    PortProp PortProps  `xml:"port"`
}

type Ports struct {
    Port PortInfo `xml:"ports"`
}

func main() {
    xmlString := `<ports>
         <extraports state="closed" count="64">
            <extrareasons reason="conn-refused" count="64" />
         </extraports>
         <port protocol="tcp" portid="22">
            <state state="open" reason="syn-ack" reason_ttl="0" />
            <service name="ssh" method="table" conf="3" />
         </port>
      </ports>`

    var x Ports
    if err := xml.Unmarshal([]byte(xmlString), &x); err == nil {
        fmt.Printf("%+v\n", x)
    } else {
        fmt.Println("err:", err)
    }

}

$ go run test.go 
{Port:{Extra:{State: Count:0 Reason:{Reason: Count:0}} PortProp:{Protocol: Port:0 StateStuff:{State: Reason:}}}}

Answer 1

Ports 所在的图层wrapper struct creates 是不必要的，删除它。您只需要对根 xml 元素的内容建模，即 <ports>其内容由 PortInfo 描述/建模.不需要包装根元素的类型。

简单的改变

var x Ports

到

var x PortInfo 

它会起作用的。在 Go Playground 上试用.输出(包装):

{Extra:{State:closed Count:64 Reason:{Reason:conn-refused Count:64}}
    PortProp:{Protocol:tcp Port:22 StateStuff:{State:open Reason:syn-ack}}}