json - 使用 Golang json.NewDecoder/json.NewEncoder

Question

我对围棋完全是个菜鸟，我试图理解我在这里错过了什么。我期望使用 dec.Decode 来循环 json 值并最终得到响应的映射。我得到的是整个 json 字符串作为 map 第一个元素的键。我错过了什么？

响应示例:

2015/03/02 10:03:16 map[error:invalid_request error_description:that is not a recognized WePay API call error_code:1001] map[string]interface {}

package main

import (
    "encoding/json"
    "io"
    "log"
    "net/http"
    "reflect"
)

func main() {
    var v map[string]interface{}
    resp, err := http.Get("https://wepayapi.com/v2/")
    if err != nil {
        log.Println("Error: " + err.Error())
    }   
    defer resp.Body.Close()

    // resp.Body is an io.ReadCloser... NewDecoder expects an io.Reader
    dec := json.NewDecoder(resp.Body)

    // Decode reads the next JSON-encoded value from its input and stores it in the value pointed to by v.
    for err := dec.Decode(&v); err != nil && err != io.EOF; {
        log.Println("ERROR: " + err.Error())
        return
    }   
    log.Println(v, reflect.TypeOf(v))
}

Answer 1

Decoder 将立即解码整个 JSON 值(在本例中为错误对象)，您不必在循环中调用它:

if err := dec.Decode(&v); err != nil {
    log.Println("ERROR: " + err.Error())
    return
}

作为响应，您将获得与此 JSON 等效的 map :

{"error":"invalid_request","error_description":"that is not a recognized WePay API call","error_code":1001}

结果:

map[string]interface{} {
    "error":"invalid_request",
    "error_description":"that is not a recognized WePay API call",
    "error_code":1001,
}