ruby - 将电话号码转换成单词

Question

所以我发现我可以通过散列来计算，问题是对于 7 和 9 我有四个值。我已经尝试了其他几件事但没有运气。有人可以帮助理解我还能做些什么来从哈希中获取我想要的值。我意识到我可以将数字与键匹配，但我对如何获得要排列的值感到困惑。

letters = {"1" => ["1", "1", "1"],
       "2" => ["a", "b", "c"],
       "3" => ["d", "e", "f"],
       "4" => ["g", "h", "i"],
       "5" => ["j", "k", "l"],
       "6" => ["m", "n", "o"],
       "7" => ["p", "q", "r", "s"],
       "8" => ["t", "u", "v"],
       "9" => ["w", "x", "y", "z"]}


phone_number = gets.chomp.to_s

words = []
word = []

numbers = phone_number.chomp.chars

count0 = 0
while count0 < 3
  count1 = 0
  while count1 < 3
    count2 = 0
    while count2 < 3
      count3 = 0
      while count3 < 3
        count4 = 0
        while count4 < 3
          count5 = 0
          while count5 < 3
            count6 = 0
            while count6 < 3
              word[0] = letters[numbers[0]][count0]
              word[1] = letters[numbers[1]][count1]
              word[2] = letters[numbers[2]][count2]
              word[3] = letters[numbers[3]][count3]
              word[4] = letters[numbers[4]][count4]
              word[5] = letters[numbers[5]][count5]
              word[6] = letters[numbers[6]][count6]
              words << word.join
              count6 += 1
            end
            count5 += 1
          end
          count4 += 1
        end
        count3 += 1
      end
      count2 += 1
    end
    count1 += 1
  end
  count0 += 1
end
puts words

---

编辑:

我想要一个七位数并打印出所有可能的字母组合。我是初学者，所以我想用我现在知道的东西来理解。我想尝试使用 if 语句执行此操作。

numbers = phone_number.chomp.chars

if letters.key?(numbers[0])
 if letters.key?(numbers[1])
  if letters.key?(numbers[2])
   if letters.key?(numbers[3])
    if letters.key?(numbers[4])
     if letters.key?(numbers[5])
      if letters.key?(numbers[6])

      end
     end
    end
   end
  end
 end 
end

我了解如何从匹配的键中获取值，但不明白如何在处理其余值的同时保留第一个值(如果这有意义的话)。

Answer 1

product 是您正在寻找的功能，以下适用于任意数量的数字:

digits = '27'
keys = digits.chars.map{|digit|letters[digit]}
p keys.shift.product(*keys).map(&:join) #=> ["ap", "aq", "ar", "as", "bp", "bq", "br", "bs", "cp", "cq", "cr", "cs"]