我写了一个 sidekiq worker 规范。所以现在我们有四个 worker ,规范几乎相同。所有规范都将测试 some_method 并检查作业是否已排队。
我的示例工作代码:
RSpec.describe HardWorker do
subject(:worker) { described_class.new }
describe "perform" do
let(:some_id) { instance_double("String") }
it "calls Hard working operation" do
expect(HardWorkingOperation).to receive(:one_method)
.with(some_id: some_id)
worker.perform(some_id)
end
it "enqueues a HardWork worker" do
HardWorker.perform_async(some_id)
expect(HardWorker.jobs.size).to eq 1
end
end
end
第二个样本规范:
RSpec.describe AnotherWorker do
subject(:worker) { described_class.new }
describe "perform" do
let(:key1){double("Integer")}
let(:key2){double("String")}
let(:options) do
{
:key1 => key1,
:key2_ref => key2
}
end
it "calls method_data" do
expect(AnotherOperation).to receive(:another_method)
.with(options["key1"], options["key2"])
worker.perform(options)
end
it "enqueues a Another worker" do
AnotherWorker.perform_async(options)
expect(AnotherWorker.jobs.size).to eq 1
end
end
end
我想写一个单一的规范来测试所有接受某种方法的 worker (可以各自不同)并且该工作已经排队。 我怎样才能最好地做到这一点?有什么建议吗?
最佳答案
您可以使用 shared examples .假设它们都有一个“操作”类来执行调用
,可能是这样的:
shared_examples_for "a sidekiq worker" do |operation_klass|
subject(:worker) { described_class.new }
describe "perform" do
let(:some_id) { instance_double("String") }
it "calls some operation" do
expect(operation_klass).to receive(:call).with(some_id: some_id)
worker.perform(some_id)
end
it "enqueues a worker" do
described_class.perform_async(some_id)
expect(described_class.jobs.size).to eq 1
end
end
end
RSpec.describe HardWorker do
it_behaves_like "a sidekiq worker", HardWorkingOperation
end
如果您还需要检查 call
是否使用每个工作人员的一组不同参数完成,我想您可以将其作为散列传递。但到那时,你应该问问自己,是否真的应该提取该规范 :P
shared_examples_for "a sidekiq worker" do |operation_klass, ops_args|
..
expect(operation_klass).to receive(:call).with(ops_args)
..
end
it_behaves_like "a sidekiq worker", HardWorkingOperation, { some_id: some_id }
关于ruby-on-rails - 使用元编程为多个工作人员编写单个规范,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/45097017/