ruby - 在 Ruby 中提取部分字符串

Question

所以我得到了一个包含以下内容的文本文件:

Blade Runner (1982) [117 min] 
Full Metal Jacket (1987) [116 min] 
Monty Python and the Holy Grail (1975) [91 min] 
The Godfather (1972) [175 min]

必须把它变成这样:

Movie name: Blade Runner  
Movie release year: 1982 
Movie length (in mins): 117 

Movie name: Full Metal Jacket  
Movie release year: 1987 
Movie length (in mins): 116 

Movie name: Monty Python and the Holy Grail  
Movie release year: 1975 
Movie length (in mins): 91 

Movie name: The Godfather  
Movie release year: 1972 
Movie length (in mins): 175

首先我遍历每一行，然后我想我应该遍历字符串的每一部分，但这就是我卡住的地方，我该怎么做？我使用正则表达式吗？如何保存与正则表达式匹配的特定字符串？

这是代码的当前外壳，它将三个部分存储到变量中，这些变量用于初始化电影类，该电影类的 to_s 方法以所需格式打印。

我知道这在很多方面都不对，但这就是我寻求帮助的原因。 variable =/regex/是为变量分配正则表达式捕获的内容的行，当/regex/用于匹配正则表达式时。

class Movie
    def initialize (name, year, length) # constructor
        @name = name
        @year = year
        @length = length
    end

    def to_s    # returns string representation of object
        return "Movie Name: " + @name
            + "\nMovie release year: "
            + @year + "\nMovie Length (in min): "
            + @length + "\n"
    end
end

$movies = []
File.open("movies.txt").each do |line|
  if matches = /(.*)? \((\d+).*?(\d+)/.match(line)
    $movies << Movie.new(matches[1], matches[2], matches[3])
  end
end


for $movie in $movies do #what u got here is not index but the element in the array
    print $movie.to_s
end

编辑:

固定版本的代码，但末尾的打印循环不起作用。

Edit2:nownit 确实如此。谢谢 PeterPeiGuo!

Answer 1

m = /(.*)? \((\d+).*?(\d+)/.match("Blade Runner (1982) [117 min]")