ruby - 如何在 Ruby 中干掉两个函数？

Question

有没有办法通过将这两个函数共享的三行移动到另一个函数来DRY up这两个 Ruby 函数？

def format_currency(number)
  number_to_currency(number, 
    :unit       => current_user.currency_unit, 
    :delimiter  => current_user.currency_delimiter, 
    :separator  => current_user.currency_separator, 
    :format     => current_user.currency_format
  )
end

def format_currency_for_pdf(number, invoice)    
  number_to_currency(number / invoice.exchange_rate, 
    :unit       => CURRENCIES[invoice.currency]
    :delimiter  => current_user.currency_delimiter, 
    :separator  => current_user.currency_separator, 
    :format     => current_user.currency_format
  )
end

感谢任何帮助？

Answer 1

正如 taro 所暗示的，它将是:

def format_currency(number)
  number_to_currency(number,
    currency_hash(current_user.currency_unit)
  )
end

def format_currency_for_pdf(number, invoice)
  number_to_currency(number / invoice.exchange_rate,
    currency_hash(CURRENCIES[invoice.currency])
  )
end

def currency_hash unit
  {
    :unit       => unit,
    :delimiter  => current_user.currency_delimiter,
    :separator  => current_user.currency_separator,
    :format     => current_user.currency_format
  }
end