python - 如何将 float 拆分并保持在一起 Ruby 和 Python

Question

我正在编写一个数学表达式检查器。我有这个字符串:

oper = "((234+3.32)+(cos4-sin65))"

我想通过分隔所有“()”和运算符减去数字或三角比来拆分此字符串以获得此结果:

oper = ['(', '(', '234', '+', '3.32', ')', '+', '(', 'cos4', '-', 'sin65', ')', ')']

如何拆分？

Answer 1

ruby :

oper = "((234+3.32)+(cos4-sin65))"
re = Regexp.union("(" ,")", "+", "-", /[^()\-+]+/)
p oper.scan(re) # => ["(", "(", "234", "+", "3.32", ")", "+", "(", "cos4", "-", "sin65", ")", ")"]