ruby - 检查部分值是否在数组内

Question

我有这个数组:

>> arr = [["a",1,"b"],["a",2,"b"],["b",3,"d"],["t",6,"a"]]

我想检查 ["a",1] 是否存在于 arr 中，同时忽略 arr 项的第三个值。

有没有更好的方法然后首先从 arr 中的每个项目中删除第三个值:

>> new_arr = [["a",1],["a",2],["b",3],["t",6]]

然后做

>> new_arr.include? ["a",1]
true

类似于:

arr.include? ["a",1,/*/]  #the 3rd value can be anything

谢谢。

Answer 1

您可以尝试以下方法:

arr = [["a",1,"b"],["a",2,"b"],["b",3,"d"],["t",6,"a"]]
arr.any? { |v1, v2, *| [v1, v2] == ["a", 1] }
# => true
arr.any? { |v1, v2, *| [v1, v2] == ["a", 4] }
# => false

包装方法中的逻辑:

def check_subarray(ary, sub_ary)
  ary.any? { |e1, e2, *| [e1, e2] == sub_ary }
end

arr = [["a",1,"b"],["a",2,"b"],["b",3,"d"],["t",6,"a"]]
check_subarray(arr, ["a", 1]) # => true