我正在寻找如何编写 format
函数的解决方案,该函数将字符串或嵌套哈希作为参数,并以路径作为键返回它的扁平化版本。
arg = "foo"
format(arg) # => { "hash[keys]" => "foo" }
arg = {:a => "foo", :b => { :c => "bar", :d => "baz" }}
format(arg) # => { "hash[keys][a]" => "foo", "hash[keys][b][c]" => "bar", "hash[keys][b][d]" => "baz" }
最佳答案
def hash_flatten h
h.inject({}) do |a,(k,v)|
if v.is_a?(Hash)
hash_flatten(v).each do |sk, sv|
a[[k]+sk] = sv
end
else
k = k ? [k] : []
a[k] = v
end
a
end
end
def format h
if h.is_a?(Hash)
a = hash_flatten(h).map do |k,v|
key = k.map{|e| "[#{e}]"}.join
"\"event[actor]#{key}\" => \"#{v}\""
end.join(', ')
else
format({nil => h})
end
end
arg = "sth"
puts format(arg)
# => "event[actor]" => "sth"
arg = {:a => "sth", :b => { :c => "sth else", :d => "trololo" }}
puts format(arg)
# => "event[actor][a]" => "sth", "event[actor][b][c]" => "sth else", "event[actor][b][d]" => "trololo"
关于ruby - 如何更改嵌套哈希的格式,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/3237107/