ruby-on-rails - 议程日历/花名册 View

Question

我想显示一个议程，显示 future 7 天谁可以参加名册，逻辑如下:

循环遍历 7 天中的每一天，对于每一天:

1. 如果休假从今天开始，显示 Starts %H:%M
2. 如果今天休假结束，则显示 Finishes %H:%M
3. 如果今天开始和结束请假，显示 %H:%M - %H:%M
4. 如果休假不是今天开始或结束，而是跨越今天，则显示 all day
5. 应包括在 7 天之外开始或结束但跨越显示的 7 天的休假。

我希望有人能为我指明正确的方向，最好使用 Rails 和 Postgres。我不反对每天查询，因为最多只会显示 30 天，但我也在寻找性能合理的代码，因为每天可能有 100 多条休假记录。

第一个不满足上述标准的示例。

<% @dates.each do |d| %>
  <h5><%= d.strftime("%A %d %b") %></h5>
  <% @leave = Leave.where('(start_at BETWEEN ? AND ?) OR (end_at BETWEEN ? AND ?)', d.beginning_of_day, d.end_of_day, d.beginning_of_day, d.end_of_day) %>
  <% @leave = @leave.where.not('end_at < ?', Time.current) %>

  <% if @leave.any? %>
    <ul>
      <% @leave.each do |leave| %>
        <% if leave.single_day? && leave.start_at.to_date == d %>
          <li>
            <label class="label label-danger"><%= leave.start_at.strftime('%H:%M') %> - <%= leave.end_at.strftime('%H:%M') %></label>
            <%= leave.user.name %>
          </li>
        <% elsif !leave.single_day? %>
          <% if leave.start_at.to_date == d %>
            <li>
              <label class="label label-danger">From <%= leave.start_at.strftime('%H:%M') %></label>
              <%= leave.user.name %>
            </li>
          <% elsif leave.end_at.to_date == d %>
            <li>
              <label class="label label-danger">Until <%= leave.end_at.strftime('%H:%M') %></label>
              <%= leave.user.name %>
            </li>
          <% else %>
            <li>
              <label class="label label-danger">All Day</label>
              <%= leave.user.name %>
            </li>
          <% end %>
        <% end %>
      <% end %>
    </ul>
    <br/>
    <span class="label label-success" style="margin-right: 10px;">
      <span class="glyphicon glyphicon-ok"></span>
    </span>
    <%= current_account.users.active.where.not(id: @leave.map(&:user_id)).count %> Available
  <% else %>
    <span class="label label-success" style="margin-right: 10px;">
      <span class="glyphicon glyphicon-ok"></span>
    </span>
    <%= current_account.users.active.count %> Available
  <% end %>

  <br />
  <br />
<% end %>

Answer 1

我会从这样的事情开始:

在模型中:

def starts_on?(date)
  start_at.to_date == date
end

def ends_on?(date)
  end_at.to_date = date
end

def covers?(date)
  leave.start_at.to_date <= date && leave.end_at.to_date >= date
end

def starts_and_ends_on?(date)
  starts_on?(date) && ends_on?(date)
end

在 Controller 中:

@dates = # define the date range like you already do, I assume it is an array
@leaves = Leave.includes(:user).
                where('start_at =< ? AND end_at >= ?', dates.max, dates.min)

在助手中:

def relevant_leaves_for_date(date, leaves)
  leaves.select { |leave| leave.covers?(date) }
end

def leave_description_for_date(leave, date)
  if leave.starts_and_ends_on?(date)
    "#{leave.start_at.strftime('%H:%M')} - #{leave.end_at.strftime('%H:%M')}"
  elsif leave.starts_on?(date)
    "From #{leave.start_at.strftime('%H:%M')}"
  elsif leave.ends_on?(date)
    "Until #{leave.end_at.strftime('%H:%M')}"
  else
    'All day'
  end
end

def available_users(leaves)
  current_account.users.active.count - leaves.size
end

在 View 中:

<% @dates.each do |date| %>
  <h5><%= date.strftime("%A %d %b") %></h5>

  <% leaves = relevant_leaves_for_date(date, @leaves) %>
  <% if leaves.any? %>
    <ul>

      <% leaves.each do |leave| %>
        <li>
          <label class="label label-danger">
            <%= leave_description_for_date(leave, date) %>
          </label>
          <%= leave.user.name %>
        </li>
      <% end %>

    </ul>
  <% end %>

  <span class="label label-success">
    <span class="glyphicon glyphicon-ok"></span>
  </span>
  <%= available_users(leaves) %> Available
<% end %>

您可能会注意到我删除了 <br>和 style来自html的标签。请不要使用 <br>造型或style html中的属性。在您的 css 文件中添加标签类和样式。