为了好玩,我正在编写自己的 Python 代码编辑器和终端,并在现有程序中实现它以增加可写性。
现在我发现了我不知道如何在代码运行后停止计算的问题。这怎么可能?
这是我的实现:
import code
import contextlib
import sys
from io import StringIO
import copy
@contextlib.contextmanager
def capture():
oldout,olderr = sys.stdout, sys.stderr
try:
out=[StringIO(), StringIO()]
sys.stdout,sys.stderr = out
yield out
finally:
sys.stdout,sys.stderr = oldout, olderr
out[0] = out[0].getvalue()
out[1] = out[1].getvalue()
class PythonTerminal(code.InteractiveConsole):
def __init__(self, shared_vars):
self.shared_vars_start = copy.deepcopy(shared_vars)
self.shared_vars = shared_vars
super().__init__(shared_vars)
self.out_history = []
def run_code(self,code_string):
with capture() as out:
self.runcode(code_string)
self.out_history.append(out)
return out
def restart_interpreter(self):
self.__init__(self.shared_vars_start)
def stop(self):
raise NotImplementedError
if __name__ == '__main__':
a = range(10)
PyTerm = PythonTerminal({'Betrag': a})
test_code = """
for i in range(10000):
for j in range(1000):
temp = i*j
print('Finished'+str(i))
"""
print('Starting')
t = threading.Thread(target=PyTerm.run_code,args=(test_code,))
t.start()
PyTerm.stop()
t.join()
print(PyTerm.out_history[-1]) # This line should be executed immediately and contain an InterruptError
目标是评估停止但解释器仍然存在,就像 ctrl+c。
最佳答案
尝试:
def stop(self):
self.resetbuffer()#abort currently executing code by wiping the input buffer
self.push("exit()")#trigger an exit from the interpreter
这两个方法的用法如下:
| push(self, line)
| Push a line to the interpreter.
|
| The line should not have a trailing newline; it may have
| internal newlines. The line is appended to a buffer and the
| interpreter's runsource() method is called with the
| concatenated contents of the buffer as source. If this
| indicates that the command was executed or invalid, the buffer
| is reset; otherwise, the command is incomplete, and the buffer
| is left as it was after the line was appended. The return
| value is 1 if more input is required, 0 if the line was dealt
| with in some way (this is the same as runsource()).
| resetbuffer(self)
| Reset the input buffer.
关于python - 中止 python 交互式控制台的评估,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/42445167/