python - 递归 Excel 文件以从树结构中查找顶级项目

标签 python python-3.x pandas recursion tree

我正在尝试递归数据集以找到最高级别的项目,即没有父项的项目。

结构如下:

╔════════════╦════════════╗
║    Item    ║  Material  ║
╠════════════╬════════════╣
║ 2094-00003 ║ MHY00007   ║
║ 2105-0001  ║ 2105-0002  ║
║ 2105-0002  ║ 2105-1000  ║
║ 2105-1000  ║ 2105-1003  ║
║ 2105-1003  ║ 7547-122   ║
║ 7932-00001 ║ 7932-00015 ║
║ 7932-00002 ║ 7932-00015 ║
║ 7932-00010 ║ MHY00007   ║
║ 7932-00015 ║ 7932-05000 ║
║ 7932-05000 ║ MHY00007   ║
╚════════════╩════════════╝

因此,例如,如果我选择 7547-122,该函数将返回 2105-0001。所以函数递归地沿着树向上,7547-122 -> 2105-1003 -> 2105-1000 -> … -> 2105-0001。

当我运行我的代码时,我只能让它返回一个顶层,正如您从 MHY00007 案例中看到的那样,有时会有多个顶层。我怎样才能返回任何给定 Material 的所有顶级列表?

我的代码:

import pandas as pd


class BillOfMaterials:

    def __init__(self, bom_excel_path):
        self.df = pd.read_excel(bom_excel_path)
        self.df = self.df[['Item', 'Material']]

    def find_parents(self, part_number):
        material_parent_search = self.df[self.df.Material == part_number]

        parents = list(set(material_parent_search['Item']))

        return parents

    def find_top_levels(self, parents):

        top_levels = self.__ancestor_finder_([parents])

        print(f'{parents} top level is {top_levels}')
        return {parents: top_levels}

    def __ancestor_finder_(self, list_of_items):

        for ancestor in list_of_items:
            print(f'Searching for ancestors of {ancestor}')
            ancestors = self.find_parents(ancestor)
            print(f'{ancestor} has ancestor(s) {ancestors}')

            if not ancestors:
                return ancestor
            else:
                highest_level = self.__ancestor_finder_(ancestors)
        return highest_level


BOM = BillOfMaterials(bom_excel_path="Path/To/Excel/File/BOM.xlsx")

ItemsToSearch = ['7547-122', 'MHY00007']

top_levels = []
for item in ItemsToSearch:
    top_levels.append(BOM.find_top_levels(item))

最佳答案

是的,您可以递归地执行此操作,例如:

import pandas as pd


class BillOfMaterials:

    def __init__(self, bom_excel_path):
        self.df = pd.read_excel(bom_excel_path)
        self.df = self.df[['Item', 'Material']]

    def find_parents(self, part_number):
        return list(set(self.df[self.df.Material == part_number]['Item']))

    def find_top_levels(self, item):
        parents = self.find_parents(item)
        if not parents:
            # there are no parent items => this item is a leaf
            return [item]
        else:
            # there are parent items => recursively find grandparents
            grandparents = []
            for parent in parents:
                grandparents = grandparents + self.find_top_levels(parent)
            return grandparents


if __name__ == '__main__':
    BOM = BillOfMaterials(bom_excel_path="testdata.xlsx")
    ItemsToSearch = ['7547-122', 'MHY00007']

    for i in ItemsToSearch:
        print('')
        print('The top levels of ' + i + ' are: ')
        print(BOM.find_top_levels(i))

注意 self.find_top_levels(parent) 的递归调用。 这将给出输出

The top levels of 7547-122 are: 
['2105-0001']

The top levels of MHY00007 are: 
['2094-00003', '7932-00001', '7932-00002', '7932-00010']

关于python - 递归 Excel 文件以从树结构中查找顶级项目,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/49342077/

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