python - 连续Python中相同的13个字符的列表

Question

到目前为止，对于我的代码，我有:

while True:
    """
    determines if there is a list of x's or o's in a horizontal row
    """
    game = list(input())
    if len(game) == 0:
        print("We should now check for vertical or diagonal winners!")
    elif game[0] == game[1]:
        if game[1] == game[2]:
            if game[2] == game[3]:
                if game[3] == game[4]:
                    if game[4] == game[5]:
                        if game[5] == game[6]:
                            if game[6] == game[7]:
                                if game[7] == game[8]:
                                    if game[8] == game[9]:
                                        if game[9] == game[10]:
                                            if game[10] == game[11]:
                                                if game[11] == game[12]:
                                                    if game[12] == "o":
                                                        print("Player o won")
                                                    else:
                                                        print("Player x won")
                                                else:
                                                    del game[0:12]
                                            else:
                                                del game[0:12]
                                        else:
                                            del game[0:12]
                                    else:
                                        del game[0:12]
                                else:
                                    del game[0:12]
                            else:
                                del game[0:12]
                        else:
                            del game[0:12]
                    else:
                        del game[0:12]
                else:
                    del game[0:12]
            else:
                del game[0:12]
        else:
            del game[0:12]
    else:
        del game[0:12]

我觉得必须有一个更短的方式来写这个。我也只是想到了一个方法来判断是否有水平的赢家。我不确定如何着手解决垂直或对角赢家。我还在第二行测试了 x winning 的代码，它没有打印 x won，所以我想知道我的错误在哪里？

非常感谢任何帮助!谢谢。

Answer 1

伙计，你急需学习正则表达式!

这看起来很像家庭作业问题，但既然其他人都在回答......我会给你最快的答案:-)。对于这个问题，Regex 可能比您用纯 Python 编写的任何东西都快，因为它使用编译的 C 代码。

您可以使用正则表达式直接从输入字符串中相当轻松地测试水平或垂直匹配。

import re

# find 13 x's or o's in a row that begin some multiple of 13 characters from the beginning of the input string
horizMatch_regex = re.compile("^(.{13})*(xxxxxxxxxxxxx|ooooooooooooo)")
# find 13 x's or o's that appear with exactly 12 characters in between, which corresponds to columns.  Requires lookahead (?=) 
verticalMatch_regex = re.compile("(x(.{12})(?=x)){12}|(o(.{12})(?=o)){12}")
# slightly trickier - you need 4 separate match groups to test for each possible diagonal.  There are a variety of ways to do that, but here's one
diagonalMatch_regex = re.compile("(^(x.{13}){12}x)|(^(o.{13}){12}o)|((x.{11}){13}.$)|((o.{11}){13}.$)")

if horizMatch_regex.search(input_str):
    print("We have a horizontal tic tac toe!")

if verticalMatch_regex.search(input_str):
    print("We have a vertical tic tac toe!")

if diagonalMatch_regex.search(input_str):
    print("We have a diagonal tic tac toe!")

# string with horizontal, vertical, and diagonal tic tac toe's
input_str = "xooooooooooooxxxxxxxxxxxxxxoxoooooooooxxxxxxxxxxxxxoxoooxoooooooxxxxxxxxxxxxxoxoooooxoooooxxxxxxxxxxxxxoxoooooooxoooxxxxxxxxxxxxxoxoooooooooxoxxxxxxxxxxxxxoxooooooooooox"

We have a horizontal tic tac toe!
We have a vertical tic tac toe!
We have a diagonal tic tac toe!