python - 使用 BeautifulSoup 从 html 中仅提取除脚本标签内容之外的文本

Question

我有这样的html

<span class="age">
    Ages 15
    <span class="loc" id="loc_loads1">
     </span>
     <script>
        getCurrentLocationVal("loc_loads1",29.45218856,59.38139268,1);
     </script>
</span>

我正在尝试使用 BeautifulSoup 提取 Age 15

于是我写了如下python代码

代码:

from bs4 import BeautifulSoup as bs
import urllib3

URL = 'html file'

http = urllib3.PoolManager()

page = http.request('GET', URL)

soup = bs(page.data, 'html.parser')
age = soup.find("span", {"class": "age"})

print(age.text)

输出:

Age 15 getCurrentLocationVal("loc_loads1",29.45218856,59.38139268,1);

我只想要 Age 15 而不是 script 标签内的函数。有没有办法只获取文本:Age 15？或者有什么方法可以排除 script 标签的内容？

PS: there are too many script tags and different URLS. I don't prefer replace text from the output.

Answer 1

使用.find(text=True)

例子:

from bs4 import BeautifulSoup

html = """<span class="age">
    Ages 15
    <span class="loc" id="loc_loads1">
     </span>
     <script>
        getCurrentLocationVal("loc_loads1",29.45218856,59.38139268,1);
     </script>
</span>"""

soup = BeautifulSoup(html, "html.parser")
print(soup.find("span", {"class": "age"}).find(text=True).strip())

输出:

Ages 15