抱歉,这不是一个好标题。简单的例子:
( Pandas 版本 0.16.1)
df = pd.DataFrame({ 'x':range(1,5), 'y':[1,1,1,9] })
工作正常:
df.apply( lambda x: x > x.mean() )
x y
0 False False
1 False False
2 True False
3 True True
这不应该是一样的吗?
df.apply( lambda x: x.mean() < x )
---------------------------------------------------------------------------
TypeError Traceback (most recent call last)
<ipython-input-467-6f32d50055ea> in <module>()
----> 1 df.apply( lambda x: x.mean() < x )
C:\Users\ei\AppData\Local\Continuum\Anaconda\lib\site-packages\pandas\core\frame.pyc in apply(self, func, axis, broadcast, raw, reduce, args, **kwds)
3707 if reduce is None:
3708 reduce = True
-> 3709 return self._apply_standard(f, axis, reduce=reduce)
3710 else:
3711 return self._apply_broadcast(f, axis)
C:\Users\ei\AppData\Local\Continuum\Anaconda\lib\site-packages\pandas\core\frame.pyc in _apply_standard(self, func, axis, ignore_failures, reduce)
3797 try:
3798 for i, v in enumerate(series_gen):
-> 3799 results[i] = func(v)
3800 keys.append(v.name)
3801 except Exception as e:
<ipython-input-467-6f32d50055ea> in <lambda>(x)
----> 1 df.apply( lambda x: x.mean() < x )
C:\Users\ei\AppData\Local\Continuum\Anaconda\lib\site-packages\pandas\core\ops.pyc in wrapper(self, other, axis)
586 return NotImplemented
587 elif isinstance(other, (np.ndarray, pd.Index)):
--> 588 if len(self) != len(other):
589 raise ValueError('Lengths must match to compare')
590 return self._constructor(na_op(self.values, np.asarray(other)),
TypeError: ('len() of unsized object', u'occurred at index x')
举个反例,这两个都有效:
df.mean() < df
df > df.mean()
最佳答案
编辑
终于找到了这个错误 - Issue 9369
如问题中所述-
left = 0 > s works (e.g. a python scalar). So I think this is being treated as a 0-dim array (its a np.int64) (and not as a scalar when called.) I'll mark as a bug. Feel free to dig in
在比较运算符的左侧使用具有 numpy
数据类型(如 np.int64 或 np.float64 等)的比较运算符时会出现此问题。一个简单的解决方法可能就像@santon 在他的回答中指出的那样,将数字转换为 python 标量,而不是使用 numpy
标量。
旧:
我在 Pandas 0.16.2 中试过。
我在您原来的 df 上做了以下操作-
In [22]: df['z'] = df['x'].mean() < df['x']
In [23]: df
Out[23]:
x y z
0 1 1 False
1 2 1 False
2 3 1 True
3 4 9 True
In [27]: df['z'].mean() < df['z']
---------------------------------------------------------------------------
TypeError Traceback (most recent call last)
<ipython-input-27-afc8a7b869b4> in <module>()
----> 1 df['z'].mean() < df['z']
C:\Anaconda3\lib\site-packages\pandas\core\ops.py in wrapper(self, other, axis)
586 return NotImplemented
587 elif isinstance(other, (np.ndarray, pd.Index)):
--> 588 if len(self) != len(other):
589 raise ValueError('Lengths must match to compare')
590 return self._constructor(na_op(self.values, np.asarray(other)),
TypeError: len() of unsized object
对我来说似乎是个错误,我可以将 bool 值与 int 进行比较,反之亦然,但只有在将 bool 值与 bool 值一起使用时才会出现问题(尽管我认为将 mean() 用于 bool 值没有意义)-
In [24]: df['z'] < df['x']
Out[24]:
0 True
1 True
2 True
3 True
dtype: bool
In [25]: df['z'] < df['x'].mean()
Out[25]:
0 True
1 True
2 True
3 True
Name: z, dtype: bool
In [26]: df['x'].mean() < df['z']
Out[26]:
0 False
1 False
2 False
3 False
Name: z, dtype: bool
我尝试并在 Pandas 0.16.1 中重现了这个问题,它也可以使用 - 重现
In [10]: df['x'].mean() < df['x']
---------------------------------------------------------------------------
TypeError Traceback (most recent call last)
<ipython-input-10-4e5dab1545af> in <module>()
----> 1 df['x'].mean() < df['x']
/opt/anaconda/envs/np18py27-1.9/lib/python2.7/site-packages/pandas/core/ops.pyc in wrapper(self, other, axis)
586 return NotImplemented
587 elif isinstance(other, (np.ndarray, pd.Index)):
--> 588 if len(self) != len(other):
589 raise ValueError('Lengths must match to compare')
590 return self._constructor(na_op(self.values, np.asarray(other)),
TypeError: len() of unsized object
In [11]: df['x'] < df['x'].mean()
Out[11]:
0 True
1 True
2 False
3 False
Name: x, dtype: bool
这似乎也是一个错误,已在 Pandas 0.16.2 版中修复(除了将 bool 值与整数混合时)。我建议使用 -
升级你的 pandas 版本pip install pandas --upgrade
关于python - 为什么比较顺序对于这个 apply/lambda 不等式很重要?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/31480885/