python - 使用 timedelta 时小数位太多

Question

我正在尝试以小时和分钟为单位查找时间，但我知道如何做到这一点的唯一方法是使用我在下面所做的事情。下面也是我的输出，如您所见，程序返回秒数和小数点。

代码:

def commercial_time (distance, speed_of_commercial):
    time = distance / speed_of_commercial
    seconds = time * 3600
    real = (datetime.timedelta(seconds = seconds))
    return real

输出:

9:46:04.352515

我的问题是，有什么办法可以去掉“.352515”吗？ 如果可能的话，我也想隐藏秒数。

Answer 1

手动格式化timedelta:

def custom_format(td):
    minutes, seconds = divmod(td.seconds, 60)
    hours, minutes = divmod(minutes, 60)
    return '{:d}:{:02d}'.format(hours, minutes)

演示:

>>> from datetime import timedelta
>>> def custom_format(td):
...     minutes, seconds = divmod(td.seconds, 60)
...     hours, minutes = divmod(minutes, 60)
...     return '{:d}:{:02d}'.format(hours, minutes)
... 
>>> custom_format(timedelta(hours=9, minutes=46, seconds=4, microseconds=352515))
'9:46'

此方法确实忽略了.days 属性。如果您的时间增量超过 24 小时，请使用:

def custom_format(td):
    minutes, seconds = divmod(td.seconds, 60)
    hours, minutes = divmod(minutes, 60)
    formatted = '{:d}:{:02d}'.format(hours, minutes)
    if td.days:
        formatted = '{} day{} {}'.format(
            td.days, 's' if td.days > 1 else '', formatted)
    return formatted

演示:

>>> custom_format(timedelta(days=42, hours=9, minutes=46, seconds=4, microseconds=352515))
'42 days 9:46'
>>> custom_format(timedelta(days=1, hours=9, minutes=46, seconds=4, microseconds=352515))
'1 day 9:46'
>>> custom_format(timedelta(hours=9, minutes=46, seconds=4, microseconds=352515))
'9:46'